Groovy/IntelliJ: groovy.lang.MissingPropertyException: 找不到属性

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英文:

Groovy/IntelliJ: groovy.lang.MissingPropertyException: No such property

问题

我是一名初学者,正在使用IntelliJ尝试构建一个样本项目并为类sampleHelper编写一些spock测试。
运行我的createToken方法的测试会导致以下错误:
groovy.lang.MissingPropertyException: No such property: sampleConstants for class: com.tutorial.sampleHelper
我的理解是同一包中的类无需导入。我一定是犯了一个愚蠢的错误,但不确定我哪里出错了。任何指针都将不胜感激。
从类中点击sampleConstants.TOKEN确实会转到正确的文件。
我有以下文件夹结构:

└── sample-project
    ├── pom.xml
    ├── resources
    ├── src --> 设置为源目录
    │      └── com
    │          └── tutorial
    │              ├── sampleConstants
    │              └── sampleHelper
    └── tests --> 设置为测试根目录
        └── com
            └── tutorial
                └── sampleHelper

sampleHelper.groovy:

package com.tutorial

public class sampleHelper implements Serializable {
    Boolean enabled

    public sampleHelper(config) {
        this.enabled = config.enabled
    }

    def createToken() {
        def token = enabled ? "abc" : sampleConstants.TOKEN
        return token
    }
}

sampleConstants.groovy

package com.tutorial

public class sampleConstants {
    static final TOKEN = "cde"
}
英文:

I'm a groovy beginner and using IntelliJ trying to build a sample project and some tests in spock for the class sampleHelper.
Running my test for the method createToken results in the following error:

groovy.lang.MissingPropertyException: No such property: sampleConstants for class: com.tutorial.sampleHelper

My understanding is that classes in the same package do not need to be imported. I must be making a silly mistake but not sure where I'm going wrong. Any pointers are appreciated.

Clicking on sampleConstants.TOKEN from the class does go to the correct file.

I have the following folder structure:

└── sample-project
    ├── pom.xml
    ├── resources
    ├── src --> set as sources root
    │   └── com
    │       └── tutorial
    │           ├── sampleConstants
    │           └── sampleHelper
    └── tests --> set as tests root
        └── com
            └── tutorial
                └── sampleHelper

sampleHelper.groovy:

package com.tutorial

public class sampleHelper implements Serializable {
    Boolean enabled

    public sampleHelper(config) {
        this.enabled = config.enabled
    }

    def createToken() {
        def token = enabled ? "abc" : sampleConstants.TOKEN
        return token
    }
}

sampleConstants.groovy

package com.tutorial

public class sampleConstants {
    static final TOKEN = "cde"
}

答案1

得分: 2

在Java(和Groovy)中,传统上类名以大写字母开头。

Groovy解析器有时会依赖于这一传统,如果您使用小写字母开头的类,它可能会难以理解您的意思,而是寻找具有该名称的字段或变量。

始终使用大写字母命名类名(以及包含它们的文件)是一个好主意,因为它可以避免像这样的情况(看起来像是世界疯了) 😉

英文:

Classes in Java (and Groovy) traditionally start with a capital letter.

The Groovy parser sometimes relies on this tradition, and if you use classes with lower-case letters, it struggles to see what you mean and instead looks for a field or variable with that name.

Always using a capital letter for class names (and the files that contain them) is always a good idea, as it saves you from things like this (which look like the world has gone mad) 😉

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  • 本文由 发表于 2023年6月19日 05:58:01
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