统计满足特定条件的文件总数在Python中

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英文:

Counting the total number of files which meet a certain criterion in Python

问题

  1. 我正在编写一个代码，它会扫描所有的文件夹并计算满足条件的所有文件的平均值：```min(numbers) <= 0.5 * max(numbers)```。然而，我还想对满足条件的所有文件夹进行总计数。我展示了当前和预期的输出。
  3. 当前输出是
  5. ```python
  6. File numbers which meet the criterion = 1
  7. File numbers which meet the criterion = 2
  8. File numbers which meet the criterion = 7
  9. File numbers which meet the criterion = 8

预期输出是

  1. File numbers which meet the criterion = 1
  2. File numbers which meet the criterion = 2
  3. File numbers which meet the criterion = 7
  4. File numbers which meet the criterion = 8
  6. Total number of files which meet the criterion = 4
英文:

I am writing a code which scans all the folders and calculates averages of all the files which meet the criterion: min(numbers) <= 0.5 * max(numbers). However, I also want to do a total count of all folders which satisfy the criterion. I present the current and expected output.

  1. import os
  3. NFILES = 10 #Scans -1 named files
  5. values = [[] for _ in range(NFILES)]
  6. Folder_name='220 nodes_seed896_var5_100stepsize_0.45initial'
  9. for i in range(NFILES):
  10.     filepath = rf"C:\Users\User\OneDrive - Technion\Research_Technion\Python_PNM\Surfactant A-D\{Folder_name}\{i}\len_J.txt"
  11.     if os.path.isfile(filepath):
  12.         with open(filepath) as data:
  13.             lines = data.readlines()
  14.             numbers = [int(line.strip()) for line in lines if line.strip().isdigit()]
  15.             if (min(numbers) <= 0.5 * max(numbers)):
  16.                 values[i].extend(numbers)
  17.                 print("File numbers which meet the criterion =",i)
  20. valid_values = [v for v in values if v]  # Remove empty lists
  24. for t in zip(*valid_values):
  25.     with open(rf"C:\Users\User\OneDrive - Technion\Research_Technion\Python_PNM\Surfactant A-D\{Folder_name}\Averaged.txt", 'a') as f:
  26.         #writer = csv.writer(f)   
  27.         #print("J =",len(J[0])) 
  28.         f.writelines('\n')
  29.         # if i < len(J[0]) - 1 and len(J[0][t + 1]) >= len(J[0][t]):
  30.         #     f.writelines('\n')
  31.         #     f.write(str(J[0]))
  32.         
  33.         f.write(str(sum(t) // len(t)))

The current output is

  1. File numbers which meet the criterion = 1
  2. File numbers which meet the criterion = 2
  3. File numbers which meet the criterion = 7
  4. File numbers which meet the criterion = 8

The expected output is

  1. File numbers which meet the criterion = 1
  2. File numbers which meet the criterion = 2
  3. File numbers which meet the criterion = 7
  4. File numbers which meet the criterion = 8
  6. Total number of files which meet the criterion = 4

答案1

得分: 1

  1.     count=0
  2.     for i in range(NFILES):
  3.     filepath = rf"C:\Users\User\OneDrive - Technion\Research_Technion\Python_PNM\Surfactant A-D\{Folder_name}\{i}\len_J.txt"
  4.     if os.path.isfile(filepath):
  5.         with open(filepath) as data:
  6.             lines = data.readlines()
  7.             numbers = [int(line.strip()) for line in lines if line.strip().isdigit()]
  8.             if (min(numbers) <= 0.5 * max(numbers)):
  9.                 values[i].extend(numbers)
  10.                 print("File numbers which meet the criterion =",i)
  11.                 count+=1
  12.     print('Total number of files which meet the criterion =',count)
  14. Here, I've used the variable 'count' to keep track of the number of files meeting the criterion.
英文: 
  1. count=0
  2. for i in range(NFILES):
  3. filepath = rf&quot;C:\Users\User\OneDrive - Technion\Research_Technion\Python_PNM\Surfactant A-D\{Folder_name}\{i}\len_J.txt&quot;
  4. if os.path.isfile(filepath):
  5.     with open(filepath) as data:
  6.         lines = data.readlines()
  7.         numbers = [int(line.strip()) for line in lines if line.strip().isdigit()]
  8.         if (min(numbers) &lt;= 0.5 * max(numbers)):
  9.             values[i].extend(numbers)
  10.             print(&quot;File numbers which meet the criterion =&quot;,i)
  11.             count+=1
  12. print(&#39;Total number of files which meet the criterion =&#39;,count)

Here, I've used the variable 'count' to keep track of the number of files meeting the criterion.

huangapple
  • 本文由 发表于 2023年6月18日 18:55:59
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