英文:
Pyspark with custom container on GCP Dataproc Serverless : access to class in custom container image
问题
我正在尝试在GCP Dataproc Serverless上使用自定义容器启动Pyspark作业，但当我尝试访问我的自定义镜像中的主类时，我发现了以下异常：
Exception in thread "main" org.apache.spark.SparkException: Failed to get main class in JAR with error '/var/dataproc/tmp/srvls-batch-10bc1778-798f-4477-b0ea-e8440770784f (Is a directory)'. Please specify one with --class.
为了重现此异常，我只创建了一个"Hello World"示例和一个基本的镜像。我的镜像托管在Google Container Registry，并且以下是其内容：
# 基础镜像FROM centos:7# 复制Python源代码COPY helloword.py helloword.py# 有用的工具RUN yum install -y curl wget procps# 版本ENV TINI_VERSION=v0.19.0# 安装tiniRUN curl -fL "https://github.com/krallin/tini/releases/download/${TINI_VERSION}/tini" -o /usr/bin/tini \&& chmod +x /usr/bin/tini# 创建 'spark' 组/用户。RUN groupadd -g 1099 sparkRUN useradd -u 1099 -g 1099 -d /home/spark -m sparkUSER spark
以下是与作业关联的命令行：
gcloud dataproc batches submit pyspark --batch name_batch file://helloword.py \--project name_project \--region europe-west9 \--version 1.1.19 \--container-image "eu.gcr.io/name_project/image-test" \--subnet default \--service-account service_account
您想要知道如何访问我的 helloword.py 吗？
提前感谢您的帮助。
英文:
I’m trying to start a job Pyspark on GCP Dataproc Serverless with custom container, but when I tried to access to my main class in my custom image, I found this exception:
Exception in thread "main" org.apache.spark.SparkException: Failed to get main class in JAR with error '/var/dataproc/tmp/srvls-batch-10bc1778-798f-4477-b0ea-e8440770784f (Is a directory)'. Please specify one with --class.
To replicate this exception, I just made a hello word and a basic image. My image is hosted on Google Container Registry and here is its contents:
# Base imageFROM centos:7# Copy the Python source codeCOPY helloword.py helloword.py# Usefull toolsRUN yum install -y curl wget procps# VersionsENV TINI_VERSION=v0.19.0# Install tiniRUN curl -fL "https://github.com/krallin/tini/releases/download/${TINI_VERSION}/tini" -o /usr/bin/tini \&& chmod +x /usr/bin/tini# Create the 'spark' group/user.RUN groupadd -g 1099 sparkRUN useradd -u 1099 -g 1099 -d /home/spark -m sparkUSER spark
and this is the command line associated to the job:
gcloud dataproc batches submit pyspark --batch name_batch file://helloword.py \--project name_project \--region europe-west9 \--version 1.1.19 \--container-image "eu.gcr.io/name_project/image-test" \--subnet default \--service-account service_account
You know how I can access to my helloword.py?
Thanks in advance.
答案1
得分: 0
由于file://helloword.py路径相对于Spark工作目录，但您已将此文件复制到容器中的Docker工作目录（默认为/），所以您看到了这个错误。
要解决此问题，您需要使用绝对路径引用此文件：file:///helloword.py。
英文:
You are seeing this error because file://helloword.py path is relative to the Spark working directory, but you have copied this file to the Docker working directory (/ by default) in your container.
To fix this issue you need to reference this file using an absolute path: file:///helloword.py
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