英文:
Pivot- turning rows to columns but keeping listing values underneath each column
问题
我是新手学习R编程，我试图将我的网站作为列，将数字列为值，并在下面单独的行中列出。这是我的数据以及我尝试做的事情。
matrix <- as.data.frame(matrix(c(1982,1923,3445,2345,12345,1234,"Site1","Site2","Site2","Site1","Site2","Site3"), nrow=6,ncol=2))matrix <- matrix %>%pivot_wider(names_from= V2, values_from = V1)
我尝试获得以下结果：
| Site1 | Site2 | Site3 |
|---|---|---|
| 1982 | 1923 | 1234 |
| 2345 | 3445 | |
| 12345 |
我需要进行pivot_longer吗？
英文:
I am new to R programming, and I am trying to get my Sites as columns and my numbers listed as values in separate rows underneath. Here's my data and what I've tried to do.
matrix <- as.data.frame(matrix(c(1982,1923,3445,2345,12345,1234,"Site1","Site2","Site2","Site1","Site2","Site3"), nrow=6,ncol=2))matrix <- matrix %>%pivot_wider(names_from= V2, values_from = V1)
I'm trying to get the following:
| Site1 | Site2 | Site3 |
|---|---|---|
| 1982 | 1923 | 1234 |
| 2345 | 3445 | |
| 12345 |
Do I need to pivot_longer?
答案1
得分: 0
这肯定还是一个 pivot_wider 操作 - 你只需生成一个用于指定唯一行以进行透视的 id 列：
library(tidyr)library(dplyr)matrix %>%group_by(V2) %>%mutate(id = row_number()) %>%pivot_wider(id_cols = id, names_from = V2, values_from = V1)## id Site1 Site2 Site3## <int> <chr> <chr> <chr>##1 1 1982 1923 1234##2 2 2345 3445 NA##3 3 NA 12345 NA
英文:
It's definitely still a pivot_wider - you just need to generate an id column to be used for specifying the unique rows to pivot against:
library(tidyr)library(dplyr)matrix %>%group_by(V2) %>%mutate(id = row_number()) %>%pivot_wider(id_cols = id, names_from= V2, values_from = V1)## id Site1 Site2 Site3## <int> <chr> <chr> <chr>##1 1 1982 1923 1234##2 2 2345 3445 NA##3 3 NA 12345 NA
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