英文:
write multiple table with different filename in R
问题
我有多个表格想要以原始名称保存为CSV文件。
这是我的示例： df.a01,df.a02,df.a03,etc.
我尝试过以下代码：
list <- list(df.a01, df.a02, df.a03)
for (i in 1:length(list)) {
write.csv(list[i], paste0(i, '.csv'), row.names = FALSE)
}
但它不起作用。
我得到了1.csv,2.csv,3.csv，但我想要的是a01.csv, a02.csv, a03.csv。
我还尝试过https://stackoverflow.com/questions/72800045/save-several-data-frames-with-different-names-with-loop，仍然无法得到我想要的结果。
非常感谢任何帮助。
英文:
I have multiple tables want to save them as csv with original names.
Here is my example : df.a01,df.a02,df.a03,etc.
I tried
list <- list(df.a01,df.a02,df.a03)
for (i in 1:length(list)) {
write.csv(list[i], paste0(i, '.csv'), row.names = FALSE)
}
but it's not work.
I got 1.csv,2.csv,3.csv,but I want to is like a01.csv,a02.csv,a03.csv.
I also tried https://stackoverflow.com/questions/72800045/save-several-data-frames-with-different-names-with-loop, still can't get what I desired.
Any help would be greatly appreciated.
答案1
得分: 0
请注意，将变量名称转换为字符串并不被视为良好的实践，即使可能可以实现（例如，参考这个线程）。
但这不是您的主要问题：当您定义列表时，您没有为其元素设置名称，因此变量名称被“丢失”（查看您的列表以查看它：names(list)）。
最后，您不应该使用函数名称来定义变量。list 是 R 中的一个函数（用于构建...列表）：因为您用您的新变量替代它，所以不能再使用该函数。
设置变量名称并在循环中使用它们的良好工作流程可能如下所示：
l = list()
l["df1"] = data.frame(t = c(1,2,3))
l["df2"] = data.frame(t = c(1,2,3))
l["df3"] = data.frame(t = c(1,2,3))
for (i in 1:length(l)){
write.csv(l[[i]], paste0(names(l)[i], '.csv'), row.names = FALSE)
}
希望这有所帮助。
英文:
Note that it is not regarded as good practice to convert variable names into string, even if it is possible (e.g. this thread).
But this is not your main problem : when you define your list, you do not set name to its elements, so the variable name are "lost" (take a look at your list to see it : names(list)).
Lastly, you shouldn't use a function name to define a variable. list is a function in R (which is used to build... list) : as you're replacing it with you're new variable, you cannot use anymore the function.
A good workflow for setting name variables and using them in a loop would look like something like this :
l = list()
l["df1"] = data.frame(t = c(1,2,3))
l["df2"] = data.frame(t = c(1,2,3))
l["df3"] = data.frame(t = c(1,2,3))
for (i in 1:length(l)){
write.csv(l[[i]], paste0(names(l)[i], '.csv'), row.names = FALSE)
}
Hope this helps
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论