英文:
" invalid date ‘TZ="UTC" @’ " error while using "date" command in bash script
问题
我正在尝试运行从互联网上获取的一些bash脚本，但它一直报错：
date: invalid date ‘TZ="UTC" @’
涉及的代码部分如下：
while [ $(date --date="TZ=\"UTC\" @$var2" +'%D') == $(date --date="TZ=\"UTC\"" +'%D') ] ; do
起初，出现了更多问题，但我通过使用双括号（"[["和"]]""）解决了一个问题（"[: ==: unary operator expected"）。
括号更改后的代码如下：
while **[[** $(date --date="TZ=\"UTC\" @$var2" +'%D') == $(date --date="TZ=\"UTC\"" +'%D') **]]** ; do
另外，我看到这个脚本应该在没有使用sudo的情况下运行。我尝试以root用户身份执行它，但即使我没有使用root用户身份，也因为权限错误而无法运行，而且我无法解决这个问题。
我认为问题可能出在--date参数上，它不能读取整个字符串，而只能读取到"@"（包括"@"）。我在论坛和网站上查找了很多，但没有找到解决我的问题的答案。有人可以帮助并可能解释一下这个while语句内部究竟发生了什么吗？
英文:
I'm trying to run some bash script I got on the internet, but it keeps spiting out error:
> date: invalid date ‘TZ="UTC" @’
Refering part of code:
while [ $(date --date="TZ=\"UTC\" @$var2" +'%D') == $(date --date="TZ=\"UTC\"" +'%D') ] ; do
At first, there were more issues, but I managed to resolve one ("[: ==: unary operator expected") by using double brackets ("[[" and "]]").
After bracket change:
while **[[** $(date --date="TZ=\"UTC\" @$var2" +'%D') == $(date --date="TZ=\"UTC\"" +'%D') **]]** ; do
Also, I read that this script should run without sudo. I was executing it as root but even when I didn't, it did not run because of a permission error that I also couldn't resolve.
My thinking is that it may be a problem with --date that can't read entire string but only to "@" ("@" included). I don't have much experience in bash, and so I was looking through forums and sites, but I couldn't find an answer to my problem. Can anyone help and maybe explain what exactly is going on inside this while statement?
答案1
得分: 1
TZ=UTC 不是日期字符串的一部分，它是您在 date 命令之外设置的环境变量：
while TZ=UTC [ "$(date --date "@$var2" +'%D')" = $(date +'%D') ] ; do
英文:
TZ=UTC isn't part of the date string, it's an environment variable you set outside the date command:
while TZ=UTC [ "$(date --date "@$var2" +'%D')" = $(date +'%D') ] ; do
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