英文:
Can't return JSONObject in the ResponseEntity properly in spring boot
问题
我正在尝试将JSON对象返回到响应实体对象的哈希映射中，以及其他字段，但对于相应值为JSON对象的字段，我得到了其他内容。
我尝试过调试，但响应流中的每个哈希映射都具有所需的响应结构。
我尝试从后端发送了这个：
HashMap<String, Object> hashMap = new HashMap<>();HashMap<String, Object> hashMap2 = new HashMap<>();JSONObject jsonObject = new JSONObject();jsonObject.put("key", "dummy value");hashMap2.put("key", "dummy value");hashMap2.put("new key", jsonObject);hashMap.put("data", jsonObject);hashMap.put("data2", hashMap2);hashMap.put("extra field", "extra value");return new ResponseEntity<>(hashMap, HttpStatusCode.valueOf(200));
但我在响应中得到了这个：
{"data": {"empty": false,"mapType": "java.util.HashMap"},"data2": {"new key": {"empty": false,"mapType": "java.util.HashMap"},"key": "dummy value"},"extra field": "extra value"}
英文:
I am trying to return the json object into the hashmap of response entity object along with other fields, but I getting something else for the fields where the corresponding value is a json object.
I tried debugging but every hashmap in the response flow was having the required response structure.
I tried sending this from the backend:
HashMap<String, Object> hashMap = new HashMap<>();HashMap<String, Object> hashMap2 = new HashMap<>();JSONObject jsonObject = new JSONObject();jsonObject.put("key", "dummy value");hashMap2.put("key", "dummy value");hashMap2.put("new key", jsonObject);hashMap.put("data", jsonObject);hashMap.put("data2", hashMap2);hashMap.put("extra field", "extra value");return new ResponseEntity<>(hashMap, HttpStatusCode.valueOf(200));
And I am getting this in the response:
{"data": {"empty": false,"mapType": "java.util.HashMap"},"data2": {"new key": {"empty": false,"mapType": "java.util.HashMap"},"key": "dummy value"},"extra field": "extra value"}
答案1
得分: 2
在Spring Boot中，你不需要将要返回为JSON的对象放在HashMap中。
相反，通常会编写一个DTO（数据传输对象）类，该类类似于你想要返回的JSON。例如，如果想返回：
{"foo": "bar","fooList": ["bar", "bar", "bar"],"fooObject": { "field": "..." }}
然后在Java中，可以编写一个DTO类如下：
public class MyDTO {private String foo;private String[] fooList; // 可以是列表private FooObject fooObject;// 获取字段访问权限的getter方法}public class FooObject {private Object object;// 获取字段访问权限的getter方法}
然后，要在Spring Boot中返回这个对象，只需将其设置为ResponseEntity上的对象：return new ResponseEntity<>(new MyDTO(...), HttpStatus.valueOf(200));
我强烈建议你采用创建特定于要返回的响应的DTO类的方法。
英文:
In Spring Boot, you do not have to box the object that you are trying to return as JSON to the client inside of a HashMap.
Instead, typically one writes a DTO (Data Transfer Object) class that resembles the JSON that you want to return. For example, if I want to return:
{"foo": "bar","fooList": ["bar", "bar", "bar"],"fooObject": { "field": "..." }}
Then in Java, I'd write a DTO class as follows:
public class MyDTO {private String foo;private String[] fooList; // Can be a list as wellprivate FooObject fooObject;// Getters to get access to the fields here}public class FooObject {private Object object;// Getters to get access to the fields here}
Then, to return this with Spring Boot, you just set it as the object on the ResponseEntity: return new ResponseEntity<>(new MyDTO(...), HttpStatusCode.valueOf(200));
I would highly suggest that you follow the approach of creating a DTO class specific to the response that you want to return.
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