英文:
How can I get a dictionary of kwargs, while only allowing certain keywords?
问题
我正在编写一个函数，需要接受多个关键字参数（kwargs），它们都默认为None，然后将它们存储在一个字典中。如果调用时使用了不支持的参数，它需要引发普通的TypeError异常。有没有比这更好的方法？
def my_function(a=None, b=None, c=None, d=None, e=None):
dictionary = {"a": a, "b": b, "c": c, "d": d, "e": e}
# ...
英文:
I am writing a function that needs to take several kwargs, all defaulting to None, and store them in a dictionary. It needs to give the normal TypeError if called with an unsupported argument. Is there a better way than this?
def my_function(a=None, b=None, c=None, d=None, e=None):
dictionary = {"a": a, "b": b, "c": c, "d": d, "e": e}
# ...
</details>
# 答案1
**得分**: 1
根据您的要求，以下是内容的中文翻译：
根据我的观点，您当前的方法是直观且最佳的，但如果您想使它更加简单，您可以尝试使用 [inspect](https://docs.python.org/3/library/inspect.html) 模块。
```python
import inspect
def my_function(a=None, b=None, c=None, d=None, e=None):
dictionary = inspect.getargvalues(inspect.currentframe()).locals
print(dictionary) # {'a': 'x', 'b': None, 'c': 1, 'd': None, 'e': [1, 2, 3]}
my_function(a="x", e=[1, 2, 3], c=1)
英文:
In my opinion, your current approach is intuitive and best, but if you want to make it even easier, you can try inspect module.
import inspect
def my_function(a=None, b=None, c=None, d=None, e=None):
dictionary = inspect.getargvalues(inspect.currentframe()).locals
print(dictionary) # {'a': 'x', 'b': None, 'c': 1, 'd': None, 'e': [1, 2, 3]}
my_function(a="x", e=[1, 2, 3], c=1)
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