How can I use my searchbar with two different values?

I've tried to add another value (organization.name) to my already successfully working searchbar, so that not only the list of SearchTerms from my organization.topic were filtered. But he doesnt add it..

    const filteredOrganizations = context.allOrganizations.filter((organization) => (organization.topic.searchTerms
        .map((term) => term.toLowerCase())
        .join(" ") ||
        organization.name)
        .includes(searchText.toLowerCase()))

thats the relevant part of my return:

<TableBody>
                            {filteredOrganizations.map((organization) => (

                                <StyledTableRow key={organization.id}>
...

I hope you have an idea

Don't use || since you want to check also the organization name.
Just concatenate the strings

const filteredOrganizations = context.allOrganizations.filter(organization => 
(
  organization.topic.searchTerms
    .map(term => term.toLowerCase()).join(' ')
    + ' ' + organization.name
)
.includes(searchText.toLowerCase()))

const searchText = 'term5'; // user input

// dummy data
const context = {
  allOrganizations: [
    {
      name: 'Organization 1',
      topic: {
        searchTerms: ['term1', 'term2'],
      },
    },
    {
      name: 'Organization 2',
      topic: {
        searchTerms: ['term5', 'term6'],
      },
    },
    {
      name: 'Organization 3',
      topic: {
        searchTerms: ['term7', 'term8'],
      },
    },
  ],
};

// filter organizations
const filteredOrganizations = context.allOrganizations.filter((organization) =>
  (
    organization.topic.searchTerms
      // remove whitespace and convert to lowercase
      .map((term) => term.trim().toLowerCase())
      // join terms into a single string
      .join(' ') +
    // add organization name
    ' ' +
    organization.name
  )
    .toLowerCase()

    // check if search text is included in the string
    .includes(searchText.trim().toLowerCase())
);

console.log(filteredOrganizations);

This was the solution:

const filteredOrganizations = context.allOrganizations.filter(organization => {
        const searchTerms = organization.topic.searchTerms.map(term => term.toLowerCase()).join(" ");
        const organizationName = organization.name.toLowerCase();
        const searchString = `${searchTerms} ${organizationName}`;

        return searchString.includes(searchText.toLowerCase());
    });