如何阻止修改数组集合状态时修改React状态?

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英文:

How to STOP React state from being modified when modifying array set to state?

问题

Trust you are having a great day!

I'm running into a serious issue with React. I have a state which holds an array. In a function I copy the state into a new variable. When I modify this newly defined variable it also updates the state which is not what I want.

Example:

const [arrayState, setArrayState] = useState(
    [
        {
            id: 'ID_1',
            text: 'item 1',
        },
        {
            id: 'ID_2',
            text: 'item 2',
        },
        {
            id: 'ID_3',
            text: 'item 3',
        },
        {
            id: 'ID_4',
            text: 'item 4',
        },
    ]
);

const myFunction = () => {
    let myVariable = [...arrayState];

    myVariable[1].text = 'myVariable item 2'; // This is modifying arrayState as well which is wrong

};

I only want myVariable to be modified and not my state (arrayState) as well.

英文:

Trust you are having a great day!

I'm running into a serious issue with React. I have a state which holds an array. In a function I copy the state into a new variable. When I modify this newly defined variable it also updates the state which is not what I want.

Example:

const [arrayState, setArrayState] = useState(
    [
        {
            id: 'ID_1'
            text: 'item 1',
        },
        {
            id: 'ID_2'
            text: 'item 2',
        },
        {
            id: 'ID_3'
            text: 'item 3',
        },
        {
            id: 'ID_4'
            text: 'item 4',
        },
    ]
);

const myFunction = () => {
    let myVariable = [...arrayState];

    myVariable[1].text = 'myVariable item 2'; // This is modifying arrayState as well which is wrong

};

I only want myVariable to be modified and not my state (arrayState) as well.

答案1

得分: 1

你可以使用 structuredClone 来对对象数组进行深度克隆。

let myVariable = structuredClone(arrayState);

或者,对于这个特定的数据结构,也可以使用以下解决方案:

let myVariable = arrayState.map(o => ({...o}));
英文:

You can use structuredClone to make a deep clone of the array of objects.

let myVariable = structuredClone(arrayState);

Alternatively, a solution that only works for this specific data structure:

let myVariable = arrayState.map(o => ({...o}));

答案2

得分: 0

这与原始值和引用值有关。数组和对象不存储值,而是引用内存中存储值的地址。一个简单的例子:

const func = () => {
    // 相同的内存引用
    const temp = arrayState;
    temp[1] = "4";
    setAttayState(temp);
}

上面的代码不会重新渲染,因为值的引用没有改变。

您必须像这样分配新的引用地址:

const func = () => {
    // 创建新的引用
    const temp = [...arrayState];
    temp[1] = "4";
    setAttayState(temp);
}
英文:

It has to do with primitive and reference values. Arrays and objects do not store values, but they refer to addresses in memory where values ​​are stored. A simple example:

const func = () => {
    // Same memory reference
    const temp = arrayState;
    temp[1] = "4";
    setAttayState(temp);
}

above code does not re-render because reference of the value has not changed.

You have to assign new reference address like this:

const func = () => {

    // Create new reference
    const temp = [...arrayState];
    temp[1] = "4";
    setAttayState(temp);
}

huangapple
  • 本文由 发表于 2023年6月13日 07:18:44
  • 转载请务必保留本文链接:https://go.coder-hub.com/76460830.html
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