英文:
How put files into zip just for pack them and no compress them in Java
问题
在Java中，可以使用ZipOutputStream来将文件打包成ZIP文件而不进行压缩。只需将多个文件打包到一个ZIP文件中，而且需要快速完成，而压缩会花费很长时间。您可以尝试使用ZipOutputStream的Stored方法，但结果的ZIP文件可能会损坏。
编辑后的代码如下：
response.setContentType("application/zip"); // zip archive format
response.setHeader(HttpHeaders.CONTENT_DISPOSITION, ContentDisposition.attachment()
.filename("download.zip", StandardCharsets.UTF_8)
.build()
.toString());
response.setContentLengthLong(totalSize);
try (ZipOutputStream zipOutputStream = new ZipOutputStream(response.getOutputStream())) {
zipOutputStream.setLevel(Deflater.NO_COMPRESSION);
for (FileSystemResource file : resources) {
try (InputStream inputStream = file.getInputStream()) {
zipOutputStream.putNextEntry(new ZipEntry(file.getFilename().toString()));
StreamUtils.copy(inputStream, zipOutputStream);
zipOutputStream.flush();
}
}
}
这段代码正常工作，但是当您添加了以下行：
zipOutputStream.setLevel(Deflater.NO_COMPRESSION);
当尝试打开最终的ZIP文件时，您会收到以下错误消息：
"无法打开，错误1，进程不存在"
没有设置压缩级别的ZIP文件通常是正常的。
英文:
Is there way in Java to pack files into zip without compression? I just need to pack many files into one, but i need it fast and compression take long time. I tried something like Stored method of ZipOutputStream but the result zip is always corrupted.
Does anybody know some solution?
EDIT:
There is my code:
response.setContentType("application/zip"); // zip archive format
response.setHeader(HttpHeaders.CONTENT_DISPOSITION, ContentDisposition.attachment()
.filename("download.zip", StandardCharsets.UTF_8)
.build()
.toString());
response.setContentLengthLong(totalSize);
try(ZipOutputStream zipOutputStream = new ZipOutputStream(response.getOutputStream())) {
zipOutputStream.setLevel(Deflater.NO_COMPRESSION);
for (FileSystemResource file : resources) {
try (InputStream inputStream = file.getInputStream()) {
zipOutputStream.putNextEntry(new ZipEntry(file.getFilename().toString()));
StreamUtils.copy(inputStream, zipOutputStream);
zipOutputStream.flush();
}
}
}
it works normal but when i added:
zipOutputStream.setLevel(Deflater.NO_COMPRESSION);
i get this error when i try to open final zip:
Could not open, ERROR 1 process doesnt exist
Zip wihtou level is always good
答案1
得分: 3
你可以使用 zipOutputStream.setLevel(Deflater.NO_COMPRESSION)。
英文:
You can use zipOutputStream.setLevel(Deflater.NO_COMPRESSION).
答案2
得分: 1
问题是您正在将响应的内容长度设置为（可能是）您正在输出的文件的长度。然而，即使没有压缩，zip文件仍然包含头部（或尾部，视情况而定）。您要么必须计算完整zip文件的长度，要么使用分块编码。
英文:
The problem is that you are setting the content length of the response to (presumably) the length of the file you are outputting. however, a zip file, even with no compression, still includes a header (or footer as the case may be). you either have to compute the length of the complete zip file, or use chunked encoding.
答案3
得分: 0
ZipOutputStream的setLevel方法是你想要的。值为'0'表示没有压缩。
链接：https://docs.oracle.com/javase/8/docs/api/java/util/zip/ZipOutputStream.html#setLevel-int-
编辑：最好使用压缩器常量NO_COMPRESSION，而不是0。
链接：https://docs.oracle.com/javase/8/docs/api/java/util/zip/Deflater.html#NO_COMPRESSION
英文:
The ZipOutputStream setLevel method is what you want. A value of '0' specifies no compression.
https://docs.oracle.com/javase/8/docs/api/java/util/zip/ZipOutputStream.html#setLevel-int-
EDIT: The best form is to use the deflator constant NO_COMPRESSION instead of 0.
https://docs.oracle.com/javase/8/docs/api/java/util/zip/Deflater.html#NO_COMPRESSION
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