HPC集群:使用多线程选项运行工具

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英文:

HPC cluster : run a tool with multithread option

问题

请使用以下翻译的部分,不包括代码:

我对Slurm作业管理器还很陌生。我想运行ADMIXTURE工具,该工具有一个多线程运行的选项。我不太理解在我的sbatch脚本中需要指定哪个选项。这是我的代码:

#!/bin/bash -l
#SBATCH -A snic2022-22-1048
#SBATCH -p core
#SBATCH --mem-per-cpu=6400
#SBATCH -n 1
#SBATCH --cpus-per-task=8
#SBATCH -t 120:59:59
#SBATCH -J ADMIXTURE

for k in {2..16}
do
    mkdir "admixk${k}"
    for i in {1..10}
    do
        admixture --cv=10 -j8 merged_dataset_light.bed $k \
            > admixk${k}/struct_k${k}_${i}.out
    done
done

其中-j8是指示我们使用8个线程运行工具的选项。ADMIXTURE的文档如下所示:

2.11 多线程模式
要将ADMIXTURE的工作分配给N个线程,您可以在ADMIXTURE命令中附加标志-jN。核心算法将以最多N倍的速度运行,假设您至少有N个处理器。

然后我不知道我是否需要像我所做的那样指定

#SBATCH -n 1
#SBATCH --cpus-per-task=8

还是

#SBATCH -n 8
#SBATCH --cpus-per-task=1

你有什么想法吗?我看到这个答案说这取决于使用的并行类型,但在这种情况下我如何知道呢?

英文:

I'm new to the slurm job manager. I want to run the tool ADMIXTURE, which has an option to run in multithreaded mode. I don't really understand which option I have to specify in my sbatch script. This is my code :

#!/bin/bash -l
#SBATCH -A snic2022-22-1048
#SBATCH -p core
#SBATCH --mem-per-cpu=6400
#SBATCH -n 1
#SBATCH --cpus-per-task=8
#SBATCH -t 120:59:59
#SBATCH -J ADMIXTURE

for k in {2..16}
do
    mkdir "admixk${k}"
    for i in {1..10}
    do
        admixture --cv=10 -j8 merged_dataset_light.bed $k \
            > admixk${k}/struct_k${k}_${i}.out
    done
done

Where -j8 is the option which indicates that we want to run the tool with 8 threads. The documentation of ADMIXTURE says the following :

> 2.11 Multithreaded mode
>To split ADMIXTURE’s work among N threads, you may append the flag -jN to your
>ADMIXTURE command. The core algorithms will run up to N times as fast, presuming
>you have at least N processors.

I don't know then if I have to specify

#SBATCH -n 1
#SBATCH --cpus-per-task=8

like I did or

#SBATCH -n 8
#SBATCH --cpus-per-task=1

Do you have any idea of how I should do that ? I saw this answer that says it depends of which type of parallelism is used, but how can I know in this case ?

答案1

得分: 1

在这种情况下,您应该使用

#SBATCH -n 1
#SBATCH --cpus-per-task=8

使用其他选项,每个任务可能会分配到另一个节点上,显然不能与线程一起使用。

英文:

In this case you should use

#SBATCH -n 1
#SBATCH --cpus-per-task=8

With the other option each task may be allocated on another node, which obviously wouldn't work with threads.

huangapple
  • 本文由 发表于 2023年6月12日 18:16:26
  • 转载请务必保留本文链接:https://go.coder-hub.com/76455644.html
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