英文:
How to loop an if statement? (Python 3.8)
问题
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英文:
After googling and diving through reddit/stackoverflow, I still haven't found a solution.
I am working on a text rpg game and I am trying to loop this statement. This is the part where the player has to choose something in the menu. There are two options:
1. Play the game
2. Go to settings
(and of course quit).
As you can see, if none of those are chosen or the player made a typo, a message should appear and restart the statement.
I tried putting the entire thing into a def function(): and I also tried using while. Probably I messed up something.
(English is not my primary language, so I am sorry if it's confusing.)
Here is the code:
while menu_input in menu_options:
if menu_input.lower() in menu_options.PLAY:
game.game()
break
elif menu_input.lower() in menu_options.HELP:
from helpsheet import *
helpsheet.helpmenu()
break
else:
print("Unknown command. For help type 'help'.")
continue
答案1
得分: 1
以下是代码的翻译部分：
你在这里没有要求菜单输入。 你需要像这样做：
while True:
menu_input = input("选择哪个选项？").lower()
if menu_input in menu_options.PLAY:
game.game()
elif menu_input in menu_options.HELP:
helpsheet.helpmenu()
elif menu_input in menu_options.QUIT:
break
else:
print("未知命令。要获取帮助，请输入 'help'。")
请注意，所有这些都会循环并再次要求输入，除了 "quit" 选项。
英文:
You're not asking for the menu input here. You need something like this:
while True:
menu_input = input("Which option?").lower()
if menu_input in menu_options.PLAY:
game.game()
elif menu_input in menu_options.HELP:
helpsheet.helpmenu()
elif menu_input in menu_options.QUIT:
break
else:
print("Unknown command. For help, type 'help'.")
Note that all of these will loop around and ask for input again, except for the "quit" options.
答案2
得分: 0
你正在使用的代码应该可以工作（至少是 while 循环部分）。唯一不起作用的原因可能是在 "you didn't give something that would work" 检查中的 "continue"，以及在答案是可用的东西时会循环的问题。另一件事是，在 while 循环中，你需要更新屏幕。（例如，创建一个显示选项的函数）
尝试：
while not menu_input in menu_options:
clear_screen() # 这不是一个实际的函数
display_screen() # 这不是一个实际的函数
if menu_input.lower() in menu_options.PLAY:
game.game()
break
elif menu_input.lower() in menu_options.HELP:
from helpsheet import *
helpsheet.helpmenu()
break
else:
print("未知命令。要获取帮助，请输入 'help'。")
menu_input = input()
"这不是一个实际的函数" 是你需要创建的函数，以使这段代码工作。
英文:
The code you're using should work (or the while loop at least) the only reasons it would not work is the "continue" in the "you didn't give something that would work" check and that your going to loop while the answer is something that you can use. Another thing though, is that in the while loop you need to update the screen. (e.g. have a function that displays your options)
Try:
while not menu_input in menu_options:
clear_screen() #Not an actual function yet
display_screen() #Not an actual function yet
if menu_input.lower() in menu_options.PLAY:
game.game()
break
elif menu_input.lower() in menu_options.HELP:
from helpsheet import *
helpsheet.helpmenu()
break
else:
print("Unknown command. For help type 'help'.")
menu_input = input()
The "Not an actual function yet" are functions that you need to create for this code to work
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