C++ expression preceding parentheses of apparent call must have (pointer-to-) function type

I overloaded parenthesis and I called but I got error.
Code is as written hereunder.

//Matrix43.h
class Matrix43 {
public:
	Matrix43();
	void operator()(
		double, double, double,
		double, double, double,
		double, double, double, 
		double, double, double);
private:
	double m00, m01, m02;
	double m10, m11, m12;
	double m20, m21, m22;
	double m30, m31, m32;
};

//Matrix43.cpp
#include "Matrix43.h"

Matrix43::Matrix43() :
	m00(0.0), m01(0.0), m02(0.0),
	m10(0.0), m11(0.0), m12(0.0),
	m20(0.0), m21(0.0), m22(0.0),
	m30(0.0), m31(0.0), m32(0.0) {
}
void Matrix43::operator()(
	double e00, double e01, double e02,
	double e10, double e11, double e12, 
	double e20, double e21, double e22, 
	double e30, double e31, double e32) {
	m00 = e00; m01 = e01; m02 = e02;
	m10 = e10; m11 = e11; m12 = e12;
	m20 = e20; m21 = e21; m22 = e22;
	m30 = e30; m31 = e31; m32 = e32;
}

I call operator like this and got error.

//main.cpp
#include "Matrix43.h"

Matrix43* a;

	int main() {
		a = new Matrix43;
//C++ expression preceding parentheses of apparent call must have (pointer-to-) function type
		*a(
			-150.0, -100.0, -300.0,
			150.0, -100.0, -300.0,
			-150.0, -100.0, 300.0,
			150.0, -100.0, 300.0
		);
		delete a;
                return 0;
	}

I found using local variable which has reference type can solve this error.

#main.cpp
#include "Math/Matrix43.h"

Matrix43* a;

	int main() {
		a = new Matrix43;
		Matrix43& o = *a;
		o(
			-150.0, -100.0, -300.0,
			150.0, -100.0, -300.0,
			-150.0, -100.0, 300.0,
			150.0, -100.0, 300.0
		);
		delete a;
                return 0
	}

But I would like to call operator through using *a so as to know exactly a is calling that.
Is there any solutions?

those codes are parts of a project, some points may looks strange.
If you have noticed, please tell me and I will add code propery.
(In the project that main function loops and I need to initialize value without constructor.)

Kind regards

When you write:

*a(1,2,3,4,5,6,7,8,9);

It is parsed as:

*(a(1,2,3,4,5,6,7,8,9));

Which is not what you wanted. So you're going to need to be more explicit with parentheses and do:

(*a)(1,2,3,4,5,6,7,8,9);