英文:
How to convert Pascal case into a separate strings?
问题
cities = ["Kyiv", "Kharkiv", "Dnipro", "Odessa", "Donetsk"]
英文:
I have a big string in Pascal case and need to make separate strings. How can I do that?
cities = ["KyivKharkivDniproOdessaDonetsk"]
end result should be
cities = ["Kyiv", "Kharkiv", "Dnipro", "Odessa", "Donetsk"]
答案1
得分: 0
如果您不喜欢使用正则表达式（有时是一个有用的工具），可以像之前的答案之一那样，使用 isupper 方法和标准的适合初学者的控制循环来完成这个任务。
cities = "KyivKharkivDniproOdessaDonetsk"
uppers = [] # 存储大写字母的索引的列表
for idx, char in enumerate(cities): # 遍历所有字符和它们的索引
if char.isupper():
uppers.append(idx)
cities_split = [] # 存储最终结果的列表
for i in range(len(uppers) - 1): # 遍历我们找到的大写字母
start_idx = uppers[i] # 选择下一个城市的起始位置
if i == len(uppers) - 1: # 在最后一个大写字母时，只需取字符串的剩余部分
cities_split.append(cities[start_idx:])
else: # 切割两个大写字母之间的部分
end_idx = uppers[i + 1]
cities_split.append(cities[start_idx:end_idx])
希望这有助于您的代码编写！
英文:
If you don't like using regex (which is sometimes an useful tool) like one of the previous answers, you could simply do this with isupper method and standard beginner-friendly control loops.
cities = "KyivKharkivDniproOdessaDonetsk"
uppers = [] # list for storing indicies of upper letters
for idx, char in enumerate(cities): # loop through all characters and their indices
if char.isupper():
uppers.append(idx)
cities_split = [] # list for storing final results
for i in range(len(uppers-1)): # loop through the uppers that we found
start_idx = uppers[i] # select the beginning of next city
if i == len(uppers)-1: # at the last upper, just take the rest of the string
cities_split.append(cities[start_idx:])
else: # slice what is inbetween two uppers
end_idx = uppers[i+1]
cities_split.append(cities[start_idx:end_idx])
答案2
得分: -2
以下是已翻译的代码部分：
这将非常简单，就像这样：
import re
cities = ["KyivKharkivDniproOdessaDonetsk"]
split_cities = re.findall(r'[A-Z][^A-Z]*', cities[0])
print(split_cities)
在上面的代码中，我们使用re.findall()函数来匹配和提取所有以大写字母（[A-Z]）开头，后跟零个或多个非大写字母（[^A-Z]*）的序列。这个模式捕获了每个以帕斯卡命名法表示的单独城市，并返回一个包含各个城市名称的列表。
结果将是['Kyiv', 'Kharkiv', 'Dnipro', 'Odessa', 'Donetsk']，如所需。
英文:
That would be as easy as this :
import re
cities = ["KyivKharkivDniproOdessaDonetsk"]
split_cities = re.findall(r'[A-Z][^A-Z]*', cities[0])
print(split_cities)
In the code above, we use the re.findall() function to match and extract all sequences that start with an uppercase letter ([A-Z]) followed by zero or more non-uppercase letters ([^A-Z]*). This pattern captures each separate city in Pascal case and returns a list of the individual city names.
The result will be ['Kyiv', 'Kharkiv', 'Dnipro', 'Odessa', 'Donetsk'], as desired.
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