英文:
Go time.Parse Invalid ISO Date
问题
有没有办法使用time.Parse解析以下日期字符串：2023-06-06T07:04:58:278-07？
我尝试使用格式2006-01-02T15:04:05:000Z07，但最后的:导致了错误。
链接：https://go.dev/play/p/y4T7meCX6D5
英文:
Is there a way to parse the following date string using time.Parse:
2023-06-06T07:04:58:278-07?
I've attempted to use the format 2006-01-02T15:04:05:000Z07, but the last : is causing an error.
答案1
得分: 2
请稍等，我会为您翻译这段代码。
英文:
Write a time.Parse wrapper function to accept a decimal point, decimal comma, or colon as the seconds decimal separator.
package main
import (
"fmt"
"strings"
"time"
)
// Accept a decimal point, decimal comma, or colon
// as the seconds decimal separator.
func timeParse(layout, value string) (time.Time, error) {
t, err := time.Parse(layout, value)
if err == nil {
return t, err
}
if strings.Count(value, ":") != 3 {
return t, err
}
i := strings.LastIndexByte(value, ':')
if i < 0 {
return t, err
}
value2 := value[:i] + "." + value[i+1:]
t2, err2 := time.Parse(layout, value2)
if err2 == nil {
return t2, err2
}
return t, err
}
func main() {
inDate := "2023-06-06T07:04:58:278-07"
parseFormat := "2006-01-02T15:04:05Z07"
t, e := timeParse(parseFormat, inDate)
if e != nil {
fmt.Println(e)
}
fmt.Println(t)
}
https://go.dev/play/p/bjk8sw5yL78
2023-06-06 07:04:58.278 -0700 -0700
答案2
得分: 1
问题在于:不是有效的分数秒分隔符。唯一允许的分隔符是.和,，正如@rocka2q所建议的那样。我相应地更改了你的示例，并成功解析了传入的日期时间。
这也得到了这两个拉取请求的确认：
如果这解决了你的问题，请告诉我，谢谢！
英文:
The issue is that : is not a valid separator for fractional seconds. The only two allowed separators are the . and the , as suggested by @rocka2q. I changed your example accordingly and I was able to parse the incoming datetime.
package main
import (
"fmt"
"time"
)
func main() {
inDate := "2023-06-06T07:04:58,158-07" // it works with the comma
// inDate := "2023-06-06T07:04:58.158-07" // it works with the dot
// inDate := "2023-06-06T07:04:58:158-07" // ":" is not a valid separator for the fractional seconds. Only "." is allowed
parseFormat := "2006-01-02T15:04:05.000-07"
t, err := time.Parse(parseFormat, inDate)
if err != nil {
fmt.Println(err)
return
}
fmt.Println(t)
}
This is also confirmed by these two Pull Requests:
Let me know if this solves your issue, thanks!
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