英文:
Javascript convert string into array
问题
我有一个以下格式的字符串，如何将此字符串转换为数组的数组，以便我可以轻松访问其中的项目？
data = '[[Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16]]'
我尝试过使用 Array.from(data)，但它没有起作用！
英文:
I have a string of the following format, how do I convert this string into an array of arrays so I can easily access the items?
data = '[[Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16]]'
I have tried Array.from(data) but it didn't work!
TIA
答案1
得分: 1
不是完美的，但应该能完成工作：
<!-- 开始片段：js 隐藏：false 控制台：true babel：false -->
<!-- 语言：lang-js -->
const data = '[[生日聚会，2023-05-16]，[生日聚会，2023-05-16]，[生日聚会，2023-05-16]，[生日聚会，2023-05-16]，[生日聚会，2023-05-16]，[生日聚会，2023-05-16]]'；
const json = JSON.parse(data.replace(/\s*([^[\],]+?)\s*(?=[,\]])/g，'"$1"'))；
console.log(json)；
<!-- 结束片段 -->
## 正则表达式的工作原理：
\s*([^[],]+?)\s*(?=[,]])
[在这里](https://regex101.com/r/cFMpVf/1) 您可以看到它的工作原理并尝试一下
| 语法 | 解释 |
| - | - |
| `\s*` | 任何空白字符，用于去除每个条目的前导空格 |
| `(` | 第一个组开始，用于捕获每个条目，例如 `生日聚会` |
| `[^[\],]+?` | 不包含 `[`，`]` 和 `,` 的一个或多个字符。`+?` 表示一个或多个但不贪婪，这是为了避免捕获尾随空格（由于某些条目在中间包含空格，我们不能排除字符集中的空格） |
| `)` | 第一个组结束，到目前为止，我们在第一个组中捕获了所需的条目，例如 `生日聚会` |
| `\s*` | 条目后的任何尾随空格，我们不需要在捕获组中 |
| `(?=[,\]])` | 一个前瞻，我们匹配的所有内容后面必须跟着 `,`（列表分隔符）或 `]`（数组的结尾） |
英文:
It's not perfect but should get the jobs done:
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
const data = '[[Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16]]';
const json = JSON.parse(data.replace(/\s*([^[\],]+?)\s*(?=[,\]])/g, '"$1"'));
console.log(json);
<!-- end snippet -->
How the regex works:
\s*([^[\],]+?)\s*(?=[,\]])
Here you can see how it works and play around a little bit
| syntax | explain |
|---|---|
\s* |
any white spaces, this is for getting rid of the leading spaces from each entry |
( |
group one start, this is for capturing each entry, such as Bday Party |
[^[\],]+? |
1 or more characters that does not contain [, ] and ,. +? means 1 or more but non-greedy, this is for avoiding capturing trailing spaces (we can't rule out white spaces inside of the character set, since some of the entries contains white spaces in the middle) |
) |
group one end, so far we have captured the entry we need in group one, such as Bday Party |
\s* |
any trailing whitespaces after an entry, we don't need that in our capturing group |
(?=[,\]]) |
a lookahead, everything we have matched must be followed by a ,(list separator) or ](end of an array) |
答案2
得分: 1
你可以使用以下的字符串拆分方法：
var data = '[[生日派对 , 2023-05-16], [生日派对 , 2023-05-16], [生日派对 , 2023-05-16], [生日派对 , 2023-05-16], [生日派对 , 2023-05-16], [生日派对 , 2023-05-16]]';
data = data.substring(2, data.length - 2);
var array = data.match(/\[.*?\]/g);
var output = [];
for (var i=0; i < array.length; ++i) {
output.push(array[i].substring(1, array[i].length - 1).split(/\s*,\s*/));
}
console.log(output);
英文:
You could use the following string splitting approach:
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
var data = '[[Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16]]';
data = data.substring(2, data.length - 2);
var array = data.match(/\[.*?\]/g);
var output = [];
for (var i=0; i < array.length; ++i) {
output.push(array[i].substring(1, array[i].length - 1).split(/\s*,\s*/));
}
console.log(output);
<!-- end snippet -->
答案3
得分: 0
许多关于正则表达式的好建议，但如果你觉得直接字符串操作更容易，这里有一个例子：
var rawData = "[[Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16]]";
var rows = rawData.slice(2, rawData.length - 2).split('], [');
var data = rows.map(x => x.split(", "));
console.log(data);
与所有答案一样，我们不知道你所接收的格式的定义，它不是标准格式，所以这段代码可能无法处理结构有变化的数据。
英文:
Many good suggestions involving regular expressions, but in case you find it easier with direct string manipulation, here's an example of that:
<!-- begin snippet: js hide: false console: true babel: false -->
<!-- language: lang-js -->
var rawData = "[[Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16], [Bday Party , 2023-05-16]]";
var rows = rawData.slice(2, rawData.length - 2).split('], [');
var data = rows.map(x => x.split(", "));
console.log(data);
<!-- end snippet -->
As with all answers, we don't know the definition of the format you're receiving, and it's not a standard one, so this snippet may not work on data with variations in structure.
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