if语句返回相同的语句,而不是根据if语句的条件而改变。

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英文:

if statement returning same statement for all results rather than changing based on the if statement

问题

"Change day Sunday"
"Change day Thursday"

英文:

I'm trying to write a simple code that will tell me if the date that I need to do something falls on a weekend. When I run this code I get the "change day" regardless of the day of the week, there is obviously something wrong with the code but I can't see it

if week_Days[movePlates.weekday()] == "Saturday" or "Sunday":
    print("change day " + str(week_Days[movePlates.weekday()]))
else: 
     print("move plates on: " + str(movePlates))


if week_Days[readPlates.weekday()] == "Saturday" or "Sunday":
    print("change day " + str(week_Days[readPlates.weekday()]))
else: 
    print("read plates on: " + str(readPlates))

Change day Sunday
Change day Thursday

答案1

得分: 0

这是隐式布尔结果的一个示例。要在你的if语句中添加括号(而不改变它):

if (week_Days[movePlates.weekday()] == "Saturday") or "Sunday":
    print("change day " + str(week_Days[movePlates.weekday()]))
else: 
     print("move plates on: " + str(movePlates))

问题在于你在or语句中处理字符串"Sunday",其中任何非空字符串都为True,因此or语句评估为True。这是一种解决方法:

if week_Days[movePlates.weekday()] == "Saturday" or week_Days[movePlates.weekday()] == "Sunday":
    print("change day " + str(week_Days[movePlates.weekday()]))
else: 
     print("move plates on: " + str(movePlates))

或者,如果你想使用不同的语法使其更简单,你可以这样做:

if week_Days[movePlates.weekday()] in ("Saturday", "Sunday"):
    print("change day " + str(week_Days[movePlates.weekday()]))
else: 
     print("move plates on: " + str(movePlates))
英文:

This is a result of implicit booleans. To add parentheses to your if statement (without changing it):

if (week_Days[movePlates.weekday()] == "Saturday") or "Sunday":
    print("change day " + str(week_Days[movePlates.weekday()]))
else: 
     print("move plates on: " + str(movePlates))

The problem is that you're treating the string "Sunday" in an or statement, where any nonempty string is True, so the or statement evaluates to True. Here's one solution:

if week_Days[movePlates.weekday()] == "Saturday" or week_Days[movePlates.weekday()] == "Sunday":
    print("change day " + str(week_Days[movePlates.weekday()]))
else: 
     print("move plates on: " + str(movePlates))

Or if you wanted to make it a little simpler with different syntax, you could do

if week_Days[movePlates.weekday()] in ("Saturday", "Sunday"):
    print("change day " + str(week_Days[movePlates.weekday()]))
else: 
     print("move plates on: " + str(movePlates))

答案2

得分: 0

你需要在if语句中对变量进行两天的测试(或使用in()运算符)。我建议将测试包装在一个函数中(如果大小写不固定,可以使用lower()):

def IsWeekend(a):
    return (a.lower() == "saturday" or a.lower() == "sunday")
英文:

You need to test the variable against both days in your if-clause (or use the in() operator). I'd suggest wrapping the test in a function (and using lower() if the casing is not fixed):

def IsWeekend(a):
    return (a.lower() == "saturday" or a.lower() == "sunday")

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  • 本文由 发表于 2023年6月9日 06:28:23
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