英文:
Type safe `as const` with Typescript
问题
当我像这样定义一个对象时，即使对象中的键不存在，它也会接受任何 string 作为对象的键。
我想要一种方式，在保持对象内容的类型安全性（如 myKey: {...}）的同时，接收类似 Property 'x' doesn't exist on FIELD_DEFS 的错误提示。
export const FIELD_DEFS: {[fieldKey: string]: FieldObj;} = {myKey: { ... }};
作为替代，我可以这样做：
export const FIELD_DEFS = {myKey: { ... } satisfies FieldObj} as const
但这种方式更冗长，而且在这种情况下 FIELD_DEFS 相当大。
英文:
When I define an object like this, it accepts any string as a key to the object even if it does not exist.
I would like some sort of way to receive an error like Property 'x' doesn't exist on FIELD_DEFS while maintaining type safety of the contents of the boject such as myKey: {...}
export const FIELD_DEFS: {[fieldKey: string]: FieldObj;} = {myKey: { ... }};
As an alternate I can do:
export const FIELD_DEFS = {myKey: { ... } satisfies FieldObj} as const
But it's more verbose and in this case FIELD_DEFS is quite large
答案1
得分: 2
不要使用 satisfies 每个字段，可以与 const assertion 结合使用：
type FieldObj= {name: string}const FIELD_DEFS = {myKey: {name: 'string'}} as const satisfies Record<string, FieldObj>
英文:
Instead of using satisfies per field, you can combine it with const assertion:
type FieldObj= {name: string}const FIELD_DEFS = {myKey: {name: 'string'}} as const satisfies Record<string, FieldObj>
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