如何在C#中不使用math.sqrt()函数计算平方根?

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英文:

How to I do a square root without using math.sqrt() in c#?

问题

When I run my program and put 0.00000001 to root nothing happens but when I put the whole number it runs fine. I'm expecting the method to work for decimals too. I also need a Message box with the message "Please enter a positive number when a negative answer is put in.

{
    int number = Convert.ToInt32(txtNumber.Text);
    double root = 1;
    int i = 0;
    //用于计算平方根的巴比伦方法
    while(true)
    {
        i = i + 1;
        root =(number / root + root)/ 2;
        if(i == number + 1){break; }
    }

    lbResult.Text = root.ToString();
}```

<details>
<summary>英文:</summary>

When I run my program and put 0.00000001 to root nothing happens but when I put the whole number it runs fine. I&#39;m expecting the method to work for decimals too. I also need a Message box with the message &quot;Please enter a positive number when a negative answer is put in.

private void btnCalc_Click(object sender, EventArgs e)
{
int number = Convert.ToInt32(txtNumber.Text);
double root = 1;
int i = 0;
//The Babylonian Method for Computing Square Roots
while (true)
{
i = i + 1;
root = (number / root + root) / 2;
if (i == number + 1) { break; }
}

        lbResult.Text = root.ToString();

}


        

</details>


# 答案1
**得分**: 2

我建议使用巴比伦算法:

```csharp
private void btnCalc_Click(object sender, EventArgs e)
{
    double number = Convert.ToDouble(txtNumber.Text);
    if (number <= 0)
    {
        MessageBox.Show("请输入一个正数");
        return;
    }
    double x = number;
    double y = 1;
    double tol = 0.000001;
    while (x - y > tol)
    {
        x = (x + y) / 2;
        y = number / x;
    }
    lbResult.Text = x.ToString();
}
英文:

I suggest a Babylonian algorithm:

private void btnCalc_Click(object sender, EventArgs e)
        {
            double number = Convert.ToDouble(txtNumber.Text);
            if(number &lt;= 0)
            {
                MessageBox.Show(&quot;Please enter a positive number&quot;);
                return;
            }
            double x = number;
            double y = 1;
            double tol = 0.000001;
            while (x - y &gt; tol)
            {
                x = (x + y) / 2;
                y = number / x;
            }
            lbResult.Text = x.ToString();
        }

答案2

得分: 1

"I'm expecting the method to work for decimals too."

然后也许不要使用输入来做这个,而是解析为除了 int 之外的其他类型:

decimal number = Convert.ToDecimal(txtNumber.Text);

你需要一个 decimal

英文:

> I'm expecting the method to work for decimals too.

Then maybe don't do this with the input, and parse to something other than int:

int number = Convert.ToInt32(txtNumber.Text);

You want a decimal:

var number = Convert.ToDecimal(txtNumber.Text);

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  • 本文由 发表于 2023年6月8日 22:40:40
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