英文:
Java sorting with lambda function
问题
请帮忙将这个函数转换为 Lambda 函数，我在类型转换方面遇到了一些问题。帮忙一下。
Arrays.sort(arr, (item1, item2) -> {double cpr1 = (double) item1.value / (double) item1.weight;double cpr2 = (double) item2.value / (double) item2.weight;if (cpr1 < cpr2) {return 1;} else {return -1;}});
英文:
Can someone please convert this function into lambda function... I am having some trouble in typecasting I guess. Help please
Arrays.sort(arr, new Comparator<Item>() {@Overridepublic int compare(Item item1, Item item2) {double cpr1 = new Double((double) item1.value / (double) item1.weight);double cpr2 = new Double((double) item2.value / (double) item2.weight);if (cpr1 < cpr2) {return 1;} else {return -1;}}});
答案1
得分: 1
我尝试了一些方法，最终找到了解决方案：
Arrays.sort(arr, (item1, item2) -> Double.compare((double) item2.value / item2.weight, (double) item1.value / item1.weight));
这将解决问题。
英文:
I tried out few things and I finally found the solution:
Arrays.sort(arr, (item1, item2) -> Double.compare((double) item2.value / item2.weight, (double) item1.value / item1.weight));
This will solve the issue.
答案2
得分: 0
public static void main(String[] args) {var arr = new Item[]{};Arrays.sort(arr, MyClass::useMySorting);}private static int useMySorting(Item item1, Item item2) {double cpr1 = new Double((double) item1.value / (double) item1.weight);double cpr2 = new Double((double) item2.value / (double) item2.weight);if (cpr1 < cpr2)return 1;elsereturn -1;}
英文:
public static void main(String[] args) {var arr = new Item[]{};Arrays.sort(arr, MyClass::useMySorting);}private static int useMySorting(Item item1, Item item2) {double cpr1 = new Double((double) item1.value / (double) item1.weight);double cpr2 = new Double((double) item2.value / (double) item2.weight);if (cpr1 < cpr2)return 1;elsereturn -1;}
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