三角形数:用Python的嵌套循环

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英文:

Triangle number: for nested loops in Python

问题

n = int(input())
for a in range(0, n+1):
    for j in range(1, a+1):
        print(j, end=' ')
    print()

输入:

5

输出:

1 
1 2 
1 2 3 
1 2 3 4 
1 2 3 4 5

在练习编程时,我遇到了一个问题。当我看到这段代码时,我不知道它是如何工作的。请帮我回答大家!谢谢大家! :))

英文:

Code snippet

n = int(input())
for a in range(0, n+1):
    for j in range(1, a+1):
        print(j, end=' ')
    print()

Input:

5

Output:

1 
1 2 
1 2 3 
1 2 3 4 
1 2 3 4 5

I had a problem while practicing coding. When I came across this piece of code, I didn't know how it worked. Please help me answer everyone!

Thanks everyone! :))

答案1

得分: 1

我的猜测是你不理解的部分是这一行:

print(j, end=' ')

它的作用是打印数字 j,然后使用 ' '(即空格)作为结束字符。
通常情况下,使用 print 函数时,默认的结束字符是 \n(在mac/linux上)或 \r\n(在Windows上),它表示换行,下一个 print 会在新的一行打印。

在这里,数字被打印出来,然后打印一个空格,而没有换行。下一个数字会在同一行的空格后面打印,因为我们没有打印换行符。
在每个第一层循环的结尾,有一个 print(),它实际上什么都不打印,但使用默认的结束字符,因此打印一个新行,下一个循环从那个新行开始。

对于这些行:

for a in range(0, n+1):
   for j in range(1, a+1):

第一行执行一个循环,范围是从 0 到 n(步长为1)。range 是左闭右开的,也就是说如果 n = 3,它会遍历 0、1、2、3。

第二个循环类似,但是范围是从 1 到 a + 1,其中 a 是第一个循环的值,因此它在每次循环运行时递增。

第二个循环运行在第一个循环内部,因此当 a = 0 时,它运行 1 到 1(1次)并打印 1,然后当 a = 2 时,它运行 j = 1 和 j = 2,并打印 1 2,当 a = 3 时,第二个循环运行 j = 1、j = 2、j = 3 并打印 1 2 3,以此类推。
第一个循环运行 n 次,所以如果 n = 5,它会打印 5 行。

英文:

my guess is that the part you don't understand is this line:

print(j, end=' ')

What it does is print the number j, and then uses ' ' (i.e. space) as the end character.
Usually with the print function, the default end character is \n (on mac/linux) or \r\n on Windows which is a line feed, and the next print prints on a new line.

Here the number is printed, and then a space is printed, without a line feed. The next number is then printed on the same line after the space because we didn't print a line feed.
At the end of each first loop, there is a print(), which effectively prints nothing but a uses the default end character, and therefore prints a new line, and the next loop over the numbers starts at that new line.

for the lines:

for a in range(0, n+1): 
   for j in range(1, a+1):

the first line does a for loop over the range 0 to n (with a step size of 1). the `range is inclusive on the left and exclusive on the right, that is if n = 3, it goes over 0, 1, 2, 3

Second loop is the same but over 1 to a + 1, a being the value from the first loop, so it increases at each run of the loop.

The second loop runs inside the first one, so when a = 0, it runs 1 to 1 (1 time) and print 1, then a = 2, it runs for j = 1 and j = 2, and prints 1 2, when a = 2, second loop runs for j = 1, j= 2, j = 3, and print 1 2 3 and so on.
The first loop runs n times, so if n = 5 it prints 5 lines.

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  • 本文由 发表于 2023年6月8日 10:34:30
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