Is there any way to set 0 as value for while rather than false? (first week of python) (SOLVED)

Below is the code that I previously made for practicing while code in Python. It was working fine

x = int(input("what is your waiting number? "))

while 1 <= x:
    
    if 1<= x <=15:
        print("customer number {} please get your coffee".format(x))
    
    elif 15 < x <= 20:
        y = 5*(x-15)
        print("please wait for another {0} min".format(y))
    
    elif 20 < x:
        print("sorry. end for today")

    x = int(input("what is your waiting number? "))

print("error. x should be bigger than 0")

But then, I wanted to simplify it and have the last print error code inside the while code.

So I've changed the condition for while to x itself (is this ok?), then added an else line with the print and break code

x = int(input("what is your waiting number? "))

while x:
    
    if 1<= x <=15:
        print("customer number {} please get your coffee".format(x))
    
    elif 15 < x <= 20:
        y = 5*(x-15)
        print("please wait for another {0} min".format(y))
    
    elif 20 < x:
        print("sorry. end for today")
    
    else:
        print("error. x should be bigger than 0")
        break

    x = int(input("what is your waiting number? "))

this seemed to work fine when x was either a positive or a negative value.

but the problem was, when I entered 0 as the value for x, the last print code before break wouldn't run.

I figured that in a 'while' code, 0 is set to false, so while x=0 will immediately terminate the code.

Is there any way to set 0 as a value for while rather than False?

SOLVED
Got an answer, was very simple.
just make the condition for while as True

while True

so that it will run without being decided by the value of x.
That case, x = 0 will also be running without problem.

Short answer : No.

Long answer :

Since you have a while x loop, for x=0, the code reads while 0. code inside the while scope is only executed if what comes after the word while evaluates to True.

Most 'empty' variables evaluate to False, no matter their type. An empty string, list or dict, 0, False...
An operation whose result is False also evaluates to False, such as 1==3.

For example :
1, True, 20<23, "foo", ['bar', 2], even negative numbers such as -10 ... all evaluate to True.
0, False, 23<20, '', [], all evaluate to False in python.

Note That None is a different case. It doesn't evaluate to True or False, but still doesn't execute while loops.

Try to execute the following code :

# These will evaluate to True.	

x=1

while x:
	print("1")
	break
	
x=True

while x:
	print("True")
	break
	
x=(20<23)

while x:
	print("(20<23)")
	break
	
x='foo'

while x:
	print("'foo'")
	break
	
x=['bar',2]

while x:
	print("['bar',2]")
	break

x=-10

while x:
	print("-10")
	break

# These will evaluate to False.	

x=0

while x:
	print("0")
	break
	
x=False

while x:
	print("False")
	break
	
x=''

while x:
	print("''")
	break
	
x=[]

while x:
	print("[]")
	break
	

# Special case : None. Neither True or False, but doesn't execute while loops either.	

x=None

while x:
	print("None")
	break

It only outputs the truthy values :

1
True
(20<23)
'foo'
['bar',2]
-10