How can I retrieve the oldest record from a joined table in SQL with distinct values for a specific column and a certain condition?

I want to get distinct vale for column "ID" with condition "Status"=1 and pick the oldest "Date".

There are 2 tables:Table1

| ID       | Code     | Date     |
|--------- | ---------|----------|
|A123      |1234      |10/9/2018 |
|A123      |7890      |9/8/2022  |
|B666      |9088      |1/2/2021  |
|C7633     |1048      |2/5/2019  |
|A123      |5477      |8/3/2022  |

Table2

| Code   | Status   | 
|------- | ---------|
|123     |1         |
|7890    |2         |
|9088    |1         |
|1048    |1         |
|5477    |1         |

I tried below sql, but it show 2 record of "ID" = A123 with "Status=1".

Select table1.ID, table1.Code, Min(table1.Date),table2.Status
From table1, table2
Where table1.Code=table2.Code
and table2.Status = '1'
Group by table1.ID, table1.Code, table2.Status;

My expected result is

Try how the result looks like with below SQL, as you expect distinct "ID", then just put "ID" after "Group by"
<!-- language-all: lang-sql -->
Select t1.ID,
Min(t1.Code) min_code,
Min(t1.Date) min_date,
Min(t2.Status) min_status
From table1 t1, table2 t2
Where t1.Code=t2.Code
and t2.Status = '1'
Group by t1.ID;