英文:
Spring WebClient POST request doesnt seem to work when passing Domain objects
问题
在传递域对象时出现了WebClient调用失败的问题，但将其作为JSON字符串传递则可以正常工作：
这个部分正常工作：
String req = "{
\"Login\": \"1121\",
\"Password\": \"1212=121\",
\"Domain\": \"corpdev.net\"
}";
String respo = webClient.post()
.uri("https://sssss.com")
.contentType(MediaType.APPLICATION_JSON)
.bodyValue(req)
.retrieve()
.bodyToMono(String.class)
.block();
但是使用域对象时不起作用：
String resp = webClient
.post()
.uri("https://sssss.com")
.contentType(MediaType.APPLICATION_JSON)
.accept(MediaType.APPLICATION_JSON)
.body(Mono.just(login), Login.class)
.retrieve()
.bodyToMono(String.class)
.block();
public class Login {
private String Login;
private String Password;
private String Domain;
}
我对Webflux有点陌生，似乎无法使其正常工作。看起来我漏掉了一些简单的东西。
英文:
Having an issue where the WebClient Call fails when passing a domain object but passing as a JSON String works :
This works :
String req="{\n" +
"\"Login\": \"1121\",\n" +
"\"Password\": \"1212=121\",\n" +
"\"Domain\": \"corpdev.net\"\n" +
"}";
String respo=webClient.post()
.uri("https://sssss.com")
.contentType(MediaType.APPLICATION_JSON)
.bodyValue(req)
.retrieve()
.bodyToMono(String.class)
.block();
but the same using a Domain object doesnt work :
String resp = webClient
.post()
.uri("https://sssss.com")
.contentType(MediaType.APPLICATION_JSON)
.accept(MediaType.APPLICATION_JSON )
.body(Mono.just(login),Login.class)
.retrieve()
.bodyToMono(String.class)
.block();
public class Login {
private String Login;
private String Password;
private String Domain;
}
I am a bit new to Webflux and cant seem to get this working . Seems like iam missing something simple . I was expecting the second option to work as it seems straight forward but they object value doesnt seem to be sent to the Rest call .
答案1
得分: 1
WebClient 使用 Jackson 库来编码内容负载。编码是通过 WebClient 委托给 Jackson2JsonEncoder 完成的。Jackson2JsonEncoder 使用 ObjectMapper（作为与 Jackson 库的高级 API 交互的组件）将您的类序列化为文本JSON表示。
问题在于，您的 Login 类在其当前形式下无法序列化为JSON。您可以执行以下操作之一：
- 在您的类上生成getter方法，例如
getLogin()、getPassword()等。 - 如果您在使用较新版本的Java，可以将
Login从class更改为record。 - 与生成getter方法不同，您可以使用
@JsonProperty注解对字段进行注解。
上述三点中的任何一点都会作为提示传递给 Jackson（执行实际编码的库），指导其如何将您的类序列化为JSON。
此外，在Java中，按照惯例，类字段名称应以小写字母开头。
因此，假设您的 Login 现在是一个 record，您可以像这样在 WebClient 中使用它：
String response = webClient.post()
.uri("https://sssss.com")
.contentType(MediaType.APPLICATION_JSON)
.bodyValue(new Login("Login", "Password", "Domain"))
.retrieve()
.bodyToMono(String.class)
.block();
英文:
WebClient uses Jackson library to encode the content payload. Encoding is delegated from WebClient to Jackson via Jackson2JsonEncoder. Jackson2JsonEncoder uses ObjectMapper (a component which acts as a high level API to the Jackson library) to serialize your class to a textual JSON representation.
And the problem is, your Login class is not serializable to JSON in its current form.
You can do one of the following:
- generate getters on your class such as
getLogin(),getPassword()etc. - if you are on recent Java, you can change
Loginfromclasstorecord - instead of generating getters, you can annotate the fields with
@JsonPropertyannotation
Any of the three points above acts as hint to Jackson (the library doing the actual encoding) how to serialize your class to JSON.
Also, it is a convention in Java to start class field names in lower case.
So assuming your Login is now a record, you can use it with WebClient like so
String respo = webClient.post()
.uri("https://sssss.com")
.contentType(MediaType.APPLICATION_JSON)
.bodyValue(new Login("Login","Password","Domain")
.retrieve()
.bodyToMono(String.class)
.block();
答案2
得分: 0
我刚刚与我的当前项目进行了比较，我能看到的唯一区别是你传递请求体的方式，你可以尝试将以下行替换为：
.body(Mono.just(login),Login.class)
替换为
.bodyValue(login)
祝好！
英文:
I've just compared with my current project and the only difference I can see is based on the way you passed the request body, can you try to replace the line :
.body(Mono.just(login),Login.class)
by
.bodyValue(login)
Regards,
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