自定义sympy函数中出现错误,尝试使用Latex打印平方函数时。

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英文:

Error in a custom sympy function when trying to print the squared function with latex

问题

我想编写一个带有特殊LaTeX输出的自定义SymPy函数一个简化的函数可能看起来像下面这样

```python
from sympy import Function, Symbol, latex

class TestClass(Function):
    def _latex(self, printer):
        m = self.args[0]
        _m = printer._print(m)
        return _m + '(x)';

S = Symbol('S')
latex(TestClass(S)**2)

然而,这给了我一个错误

TypeError: TestClass._latex() 收到了一个意外的关键字参数 'exp'

请问有人可以帮我理解这里出了什么问题吗?


<details>
<summary>英文:</summary>

I would like to write a custom SymPy Function with special latex output. A simplified function might look like the following:


```python
from sympy import Function, Symbol, latex

class TestClass(Function):
    def _latex(self, printer):
        m = self.args[0]
        _m = printer._print(m)
        return _m + &#39;(x)&#39;

S = Symbol(&#39;S&#39;)
latex(TestClass(S)**2)

However, this gives me the error
> TypeError: TestClass._latex() got an unexpected keyword argument 'exp'

Can someone please help me to understand what is going wrong here?

答案1

得分: 1

TestClassFunction 的子类。

TestClass(S)**2Pow 的一个实例。让我们看一下 LatexPrinter 类的源代码,具体是 _print_Pow 方法:

        if expr.base.is_Function:
            return self._print(expr.base, exp=self._print(expr.exp))

在底层,self._print 检查 expr.base 是否实现了 _latex 方法。如果是的话(就像在你的测试案例中一样),它会调用它并传递关键字参数 exp

所以,你需要调整你的代码:

class TestClass(Function):
    def _latex(self, printer, exp=None):
        m = self.args[0]
        _m = printer.doprint(m)
        base = _m + '(x)'
        if exp is None:
            return base
        return base + "^{%s}" % exp

S = Symbol('S')
expr = TestClass(S)
latex(expr**3)
# 输出: 'S(x)^{3}'
英文:

TestClass is a subclass of Function.

TestClass(S)**2 is an instance of Pow. Let's look at the source code of the LatexPrinter class, specifically at the _print_Pow method:

        if expr.base.is_Function:
            return self._print(expr.base, exp=self._print(expr.exp))

Under the hood, self._print checks if expr.base implements the _latex method. If it does (like in your test case), it calls it and pass along the keyword arguments, exp.

So, you need to adjust your code:

class TestClass(Function):
    def _latex(self, printer, exp=None):
        m = self.args[0]
        _m = printer.doprint(m)
        base = _m + &#39;(x)&#39;
        if exp is None:
            return base
        return base + &quot;^{%s}&quot; % exp

S = Symbol(&#39;S&#39;)
expr = TestClass(S)
latex(expr**3)
# out: &#39;S(x)^{3}&#39;

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  • 本文由 发表于 2023年6月6日 01:09:18
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