团队报告,包括页眉和详细信息?

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英文:

Group Report With Header and Detail?

问题

我有一个名为“transactions”的表,其中包含以下详细信息

id dt_trans category description amount
1 2022-08-05 Expense Food 60.00
2 2022-08-05 Travel Petrol 20.00
2 2022-08-08 Travel Petrol 20.00

然后我想根据以下报告创建报告

dt_trans category description amount
Expense
1 2022-08-05 Expense Food 60.00
Total 60.00
Travel
1 2022-08-05 Travel Petrol 20.00
2 2022-08-08 Travel Petrol 20.00
Total 40.00

通常情况下,我会基于报告创建一个临时表,并基于2个查询添加行。以下是逻辑

循环 // 查询1 检索所有类别

   查询2 根据类别检索所有详细信息

循环结束 查询1

是否有更简单的方法来创建此报告?

查询:

如果存在,则删除表`transaction`;
创建表`transaction` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `cashaccount_id` int(11) DEFAULT NULL,
  `dt_trans` date DEFAULT NULL,
  `category` varchar(200) DEFAULT NULL,
  `description` varchar(500) DEFAULT NULL,
  `type` tinyint(4) DEFAULT NULL COMMENT '0 income 1 expense',
  `amount` float(10,2) DEFAULT 0.00,
  `dt_created` datetime DEFAULT NULL,
  `uid` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 COLLATE=latin1_swedish_ci;

向表`transaction`中插入值 (`id`, `cashaccount_id`, `dt_trans`, `category`, `description`, `type`, `amount`, `dt_created`, `uid`) VALUES
(115, 1, '2021-10-10', 'Expense', 'Food', 1, 60.00, '2021-10-10 17:06:36', 1),
(121, 1, '2021-10-15', 'Travel', 'Petrol', 1, 20.00, '2021-10-15 01:01:15', 1),
(123, 1, '2021-10-05', 'Travel', 'Petrol', 0, 20.00, '2021-10-15 09:11:28', 1)
英文:

I have table transactions with below details

id dt_trans category description amount
1 2022-08-05 Expense Food 60.00
2 2022-08-05 Travel Petrol 20.00
2 2022-08-08 Travel Petrol 20.00

then I want to create report based on below report

dt_trans category description amount
Expense
1 2022-08-05 Expense Food 60.00
Total 60.00
Travel
1 2022-08-05 Travel Petrol 20.00
2 2022-08-08 Travel Petrol 20.00
Total 40.00

Usually I will create a temporary table based on the report and add the row based on 2 queries.
Here's the logic

Loop // query1 retrieve all the category

   query2 retrieve all the details based on category

end of loop query1

Is there a more simple way to create this report?

query:

DROP TABLE IF EXISTS `transaction`;
CREATE TABLE `transaction` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `cashaccount_id` int(11) DEFAULT NULL,
  `dt_trans` date DEFAULT NULL,
  `category` varchar(200) DEFAULT NULL,
  `description` varchar(500) DEFAULT NULL,
  `type` tinyint(4) DEFAULT NULL COMMENT '0 income 1 expense',
  `amount` float(10,2) DEFAULT 0.00,
  `dt_created` datetime DEFAULT NULL,
  `uid` int(11) DEFAULT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 COLLATE=latin1_swedish_ci;

INSERT INTO `transaction` (`id`, `cashaccount_id`, `dt_trans`, `category`, `description`, `type`, `amount`, `dt_created`, `uid`) VALUES
(115, 1, '2021-10-10', 'Expense', 'Food', 1, 60.00, '2021-10-10 17:06:36', 1),
(121, 1, '2021-10-15', 'Travel', 'Petrol', 1, 20.00, '2021-10-15 01:01:15', 1),
(123, 1, '2021-10-05', 'Travel', 'Petrol', 0, 20.00, '2021-10-15 09:11:28', 1)

答案1

得分: 1

尝试使用以下特定顺序将三个选择语句合并:

获取所有用户的报告:

with t as
(
  select id, dt_trans, category, description, amount, uid,
       dense_rank() over (order by uid, category) as ord1, 2 as ord2
  from transaction

  union all

  select distinct category, '', '', '', '', uid,
         dense_rank() over (order by uid, category) as ord1,
         1 as ord2
  from transaction 

  union all

  select  '', '', '', 'Total', 
          sum(amount), uid,
          dense_rank() over (order by uid, category) as ord1, 
          3 as ord2 
  from transaction 
  group by category, uid
)
select uid, id, dt_trans, category, description, amount
from t
order by uid, ord1, ord2

获取单个用户的报告:

with t as
(
  select id, dt_trans, category, description, amount,
       dense_rank() over (order by category) as ord1, 2 as ord2
  from transaction where uid = 1

  union all

  select distinct category, '', '', '',
         dense_rank() over (order by category) as ord1,
         1 as ord2
  from transaction where uid = 1

  union all

  select  '', '', '', 'Total', 
          sum(amount),
          dense_rank() over (order by category) as ord1, 
          3 as ord2 
  from transaction where uid = 1
  group by category 
)
select id, dt_trans, category, description, amount
from t
order by ord1, ord2

但最好在SQL服务器之外执行此类格式化报告。

英文:

Try to union three select statements with a specific order for each one as the following:

To get the report for all users:

with t as
(
  select id, dt_trans, category, description, amount, uid,
       dense_rank() over (order by uid, category) as ord1, 2 as ord2
  from transaction
  
  union all
  
  select distinct category, '', '', '', '', uid,
         dense_rank() over (order by uid, category) as ord1,
         1 as ord2
  from transaction 
  
  union all
  
  select  '', '', '', 'Total', 
          sum(amount), uid,
          dense_rank() over (order by uid, category) as ord1, 
          3 as ord2 
  from transaction 
  group by category, uid
)
select uid, id, dt_trans, category, description, amount
from t
order by uid, ord1, ord2

demo

To get the report for a single user:

with t as
(
  select id, dt_trans, category, description, amount,
       dense_rank() over (order by category) as ord1, 2 as ord2
  from transaction where uid = 1
  
  union all
  
  select distinct category, '', '', '', '',
         dense_rank() over (order by category) as ord1,
         1 as ord2
  from transaction where uid = 1
  
  union all
  
  select  '', '', '', 'Total', 
          sum(amount),
          dense_rank() over (order by category) as ord1, 
          3 as ord2 
  from transaction where uid = 1
  group by category 
)
select id, dt_trans, category, description, amount
from t
order by ord1, ord2

demo

But it would be better to perform this kind of formatting reports outside the SQL server.

答案2

得分: 1

尝试使用 ROLLUP。示例:

select category head,rn, max(dt_trans)dt_trans,category,max(description)description,sum(amount) amount
from(
select *
  ,row_number()over(partition by category order by category desc,dt_trans) rn
from transaction
) t
group by category ,rn with rollup

结果。rn 中有空值 - 按类别汇总,head 和 rn 中都有空值 - 汇总报告。

|head| rn | dt_trans | category | description | amount |
|:----|-:--|:----------|:---------|:------------|-------:|
|支出 | 1 | 2021-10-10 | 支出 | 食物 | 60.00 |
|支出 |null| 2021-10-10 | 支出 | 食物 | 60.00 |
|旅行 | 1 | 2021-10-05 | 旅行 | 汽油 | 20.00 |
|旅行 | 2 | 2021-10-15 | 旅行 | 汽油 | 20.00 |
|旅行 |null| 2021-10-15 | 旅行 | 汽油 | 40.00 |
|null |null| 2021-10-15 |null | 汽油 |100.00 |

英文:

Try use ROLLUP. Example

select category head,rn, max(dt_trans)dt_trans,category,max(description)description,sum(amount) amount
from(
select *
  ,row_number()over(partition by category order by category desc,dt_trans) rn
from transaction
) t
group by category ,rn with rollup

Result. There null in rn - totals by category, null in both head and rn - report totals.

head rn dt_trans category description amount
Expense 1 2021-10-10 Expense Food 60.00
Expense null 2021-10-10 Expense Food 60.00
Travel 1 2021-10-05 Travel Petrol 20.00
Travel 2 2021-10-15 Travel Petrol 20.00
Travel null 2021-10-15 Travel Petrol 40.00
null null 2021-10-15 null Petrol 100.00

答案3

得分: 0

以下是翻译好的部分:

你可以尝试在编程方面循环,但这里是一个简单的mysql查询

SELECT
s.*
FROM
transaction s
CROSS JOIN
(SELECT
category
FROM
transaction) AS t
GROUP BY s.id

英文:

You may try to loop on programming side but here is a simple mysql query

SELECT 
    s.*
FROM
    transaction s
        CROSS JOIN
    (SELECT 
        category
    FROM
        transaction) AS t
        GROUP BY s.id

huangapple
  • 本文由 发表于 2023年6月5日 15:04:45
  • 转载请务必保留本文链接:https://go.coder-hub.com/76404160.html
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