如何将光标向上移动2行到开头？

huangapple
go评论118阅读模式
英文:

How do I move the cursor 2 lines up to the beginning?

问题

如何将光标上移 2 行并返回到开头？

我有一个应用程序，它将一些数据输出到控制台，然后启动一个定时器来更新数据。整个输出看起来像这样：

  1. 重要数据 1
  2. 重要数据 2
  3. 重要数据 3
  4. 01 分钟 51 秒后的下一个更新数据...
  5. 要停止程序，请按 Ctrl+E

但是当定时器的大小变小时，该行没有完全擦除：

  1. > 55 秒后的下一个更新数据...秒...

它应该是：

  1. > 55 秒后的下一个更新数据...

我知道为什么会发生这种情况，并且我有一个避免这种效果的想法，我只需在输出行之前用空格填充它。我想要输出空行以擦除旧数据并输出更新的计时器。

  1. clear_line_timer = ''.join(" " for i in range(len_line_timer))
  2. clear_line_info = ''.join(" " for i in range(len_line_info))
  3. line_timer = 'Next update data after ' + timerToString(seconds) + ' ...'
  4. line_info = 'To stop the program, press Ctrl+E'
  5. len_line_timer = len(line_timer)
  6. len_line_info = len(line_info)

理论上，这应该可以工作，**但我不知道如何将光标指针返回到计时器行的开头。如何在输出之前将光标返回到计时器行的开头？**我希望它的工作方式与Windows和Linux/Unix类似。

用于回放的完整代码

  1. import time
  3. len_line_timer = 0
  4. len_line_info = 0
  7. def timerToString(seconds: int) -> str:
  8.     if seconds is not None:
  9.         seconds = int(seconds)
  10.         d = seconds // (3600 * 24)
  11.         h = seconds // 3600 % 24
  12.         m = seconds % 3600 // 60
  13.         s = seconds % 3600 % 60
  14.         if d > 0:
  15.             return '{:02d}d {:02d}h {:02d}m {:02d}s'.format(d, h, m, s)
  16.         elif h > 0:
  17.             return '{:02d}h {:02d}m {:02d}s'.format(h, m, s)
  18.         elif m > 0:
  19.             return '{:02d} minutes {:02d} seconds'.format(m, s)
  20.         elif s > 0:
  21.             return '{:02d} seconds'.format(s)
  22.     return 'now';
  25. def timer(seconds):
  26.     global len_line_timer
  27.     global len_line_info
  29.     clear_line_timer = ''.join(" " for i in range(len_line_timer))
  30.     clear_line_info = ''.join(" " for i in range(len_line_info))
  31.     line_timer = 'Next update data after ' + timerToString(seconds) + ' ...'
  32.     line_info = 'To stop the program, press Ctrl+E'
  33.     len_line_timer = len(line_timer)
  34.     len_line_info = len(line_info)
  35.     ####################################################################################
  36.     # 你需要以某种方式将光标指针返回到计时器行的开头 #
  37.     ####################################################################################
  38.     print(clear_line_timer + '\r', end='')
  39.     print(line_timer + '\r', end='')
  40.     print(clear_line_info + '\r', end='')
  41.     print(line_info + '\r', end='')
  44. if __name__ == '__main__':
  45.     print("重要数据 1")
  46.     print("重要数据 2")
  47.     back_timer = 70
  48.     counter = back_timer
  49.     while True:
  51.         timer(counter)
  53.         counter -= 1
  54.         time.sleep(1)
  55.         if counter <= 0:
  56.             counter = back_timer
英文:

How do I move the cursor 2 lines up to the beginning?

I have an application that outputs some data to the console, after which it turns on a timer to update the data. The whole output looks like this

  1. Important data 1
  2. Important data 2
  3. Important data 3
  4. Next update data after 01 minutes 51 seconds ...
  5. To stop the program, press Ctrel+E

But there is a problem when the timer size becomes smaller, the line is not completely erased

> Next update data after 55 seconds ...seconds ...

And it should be

> Next update data after 55 seconds ...

I know why this is happening, and I had an idea to avoid such an effect, I'll just fill it with spaces before outputting a line.
I want to output empty lines to erase the old data and output an updated timer

  1. clear_line_timer = &#39;&#39;.join(&quot; &quot; for i in range(len_line_timer))
  2. clear_line_info = &#39;&#39;.join(&quot; &quot; for i in range(len_line_info))
  3. line_timer = &#39;Next update data after &#39; + timerToString(seconds) + &#39; ...&#39;
  4. line_info = &#39;To stop the program, press Ctrl+E&#39;
  5. len_line_timer = len(line_timer)
  6. len_line_info = len(line_info)

In theory, this should work, but I do not know how to return the cursor pointer to the beginning of the line with a timer.
How can I return the cursor to the beginning of the timer line before output?
I want it to work like in Windows and Linux/Unix

Full code for playback

  1. import time
  2. len_line_timer = 0
  3. len_line_info = 0
  4. def timerToString(seconds: int) -&gt; str:
  5. if seconds is not None:
  6. seconds = int(seconds)
  7. d = seconds // (3600 * 24)
  8. h = seconds // 3600 % 24
  9. m = seconds % 3600 // 60
  10. s = seconds % 3600 % 60
  11. if d &gt; 0:
  12. return &#39;{:02d}d {:02d}h {:02d}m {:02d}s&#39;.format(d, h, m, s)
  13. elif h &gt; 0:
  14. return &#39;{:02d}h {:02d}m {:02d}s&#39;.format(h, m, s)
  15. elif m &gt; 0:
  16. return &#39;{:02d} minutes {:02d} seconds&#39;.format(m, s)
  17. elif s &gt; 0:
  18. return &#39;{:02d} seconds&#39;.format(s)
  19. return &#39;now&#39;
  20. def timer(seconds):
  21. global len_line_timer
  22. global len_line_info
  23. clear_line_timer = &#39;&#39;.join(&quot; &quot; for i in range(len_line_timer))
  24. clear_line_info = &#39;&#39;.join(&quot; &quot; for i in range(len_line_info))
  25. line_timer = &#39;Next update data after &#39; + timerToString(seconds) + &#39; ...&#39;
  26. line_info = &#39;To stop the program, press Ctrl+E&#39;
  27. len_line_timer = len(line_timer)
  28. len_line_info = len(line_info)
  29. ####################################################################################
  30. # You need to somehow return the cursor pointer to the beginning of the timer line #
  31. ####################################################################################
  32. print(clear_line_timer + &#39;\r&#39;, end=&#39;&#39;)
  33. print(line_timer + &#39;\r&#39;, end=&#39;&#39;)
  34. print(clear_line_info + &#39;\r&#39;, end=&#39;&#39;)
  35. print(line_info + &#39;\r&#39;, end=&#39;&#39;)
  36. if __name__ == &#39;__main__&#39;:
  37. print(&quot;Important data 1&quot;)
  38. print(&quot;Important data 2&quot;)
  39. back_timer = 70
  40. counter = back_timer
  41. while True:
  42. timer(counter)
  43. counter -= 1
  44. time.sleep(1)
  45. if counter &lt;= 0:
  46. counter = back_timer

答案1

得分: 0

FYI，这实际上不是一个python问题，更像是一个Linux shell问题（或者如果你在使用Windows的话，那就是Windows的问题）。

对于兼容bash的shell，有一些控制代码可以移动光标：https://tldp.org/HOWTO/Bash-Prompt-HOWTO/x361.html。只需像平常一样从python的STDOUT中print()这些代码即可。

你也可以查看https://pypi.org/project/ansi-escapes/，它正好可以做到这一点。

英文:

FYI, this isn't really a python question, more of a Linux shell question (or Windows, if that's what you're using).

For bash-compatible shells, there are control codes to move the cursor around: https://tldp.org/HOWTO/Bash-Prompt-HOWTO/x361.html. Just print() these codes to STDOUT from python as normal.

You can also check out https://pypi.org/project/ansi-escapes/ which does exactly this.

答案2

得分: 0

以下是要翻译的内容：

我在终端中使用这个bash函数来进行文本定位：

文本定位，用法：XY 10 10 'Hello World!'

XY () { printf "\e[$2;${1}H$3"; }

英文:

I'm using this bash function for text positioning in terminal:

  1. # Text positioning, usage: XY 10 10 &#39;Hello World!&#39;
  2. XY () { printf &quot;\e[$2;${1}H$3&quot;; }

huangapple
  • 本文由 发表于 2023年6月5日 12:19:02
  • 转载请务必保留本文链接：https://go.coder-hub.com/76403477.html
  • python
  • shell
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定