英文:
best practice to update a field in list of dictionary of list and dictionary
问题
你想要更新这个部分，将"aaaa"和"bbb"添加进去：
"instance[]": [
{
"key": "requires",
"value": {
"string[]": ["aaaa", "bbb"]
}
你可以使用以下方法来更新它：
# 找到包含"key"为"order"的字典
newl = [d for d in test if d["key"] == "order"]
# 检查是否找到了匹配的字典
if newl:
# 在匹配的字典中找到"instance[]"部分
instance_list = newl[0]["value"]["instance[]"]
# 在"requires"字典中添加"aaaa"和"bbb"
for instance in instance_list:
if instance["key"] == "order_det":
instance["value"]["instance[]"][0]["value"]["string[]"].extend(["aaaa", "bbb"])
# 打印更新后的test列表
print(test)
这将会更新你的test列表，添加"aaaa"和"bbb"到指定的位置。
英文:
Assuming the input is a list of dictionary.
I need to update a specific field with new values.
There are repeated keys, values in the input so cannot distinguish the field need to be picked by its name.
Here is an example:
test = [
{
"key": "prog",
"value": {
"instance[]": [
{
"key": "name",
"value": {
"string": "NAME"
},
"verif": 22222222
},
{
"key": "user",
"value": {
"string": "AAAAA"
},
"verif": 22222222
}
]
},
"verif": 22222222
},
{
"key": "sytem_platform",
"value": {
"bool": "false"
},
"verif": 22222222
},
{
"key": "system_beh",
"value": {
"bool": "true"
},
"verif": 22222222
},
{
"key": "check_beh",
"value": {
"bool": "true"
},
"verif": 22222222
},
{
"key": "order",
"value": {
"instance[]": [
{
"key": "order_det",
"value": {
"instance[]": [
{
"key": "requires",
"value": {
"string[]": []
},
"verif": 22222222
},
{
"key": "status",
"value": {
"string[]": []
},
"verif": 22222222
},
{
"key": "system_status",
"value": {
"string[]": [
"sys1.out",
"sys1.checking"
]
},
"verif": 22222222
},
{
"key": "weather_status",
"value": {
"instance[]": [
{
"key": "humdiity",
"value": {
"double": 5.0
},
"verif": 22222222
},
{
"key": "temp",
"value": {
"double": 70.0
},
"verif": 22222222
}
]
},
"verif": 22222222
},
{
"key": "environment",
"value": {
"string[]": []
},
"verif": 22222222
}
]
},
"verif": 22222222
}
]
},
"verif": 22222222
}
]
I am trying to update the following section of it like adding "aaaa" and "bbb"
"instance[]": [
{
"key": "requires",
"value": {
"string[]": ["aaaa", "bbb"]
},
I was wondering if there is any built-in library in python that i can use for this goal?
i can filter it out and store it in a list like below, but i am not sure how i can update it.
newl = [d for d in test if d["key"] == "order" ]
print(newl)
#which prints
[{'key': 'order', 'value': {'instance[]': [{'key': 'order_det', 'value': {'instance[]': [{'key': 'requires', 'value': {'string[]': []}, 'verif': 22222222}, {'key': 'status', 'value': {'string[]': []}, 'verif': 22222222}, {'key': 'system_status', 'value': {'string[]': ['sys1.out', 'sys1.checking']}, 'verif': 22222222}, {'key': 'weather_status', 'value': {'instance[]': [{'key': 'humdiity', 'value': {'double': 5.0}, 'verif': 22222222}, {'key': 'temp', 'value': {'double': 70.0}, 'verif': 22222222}]}, 'verif': 22222222}, {'key': 'environment', 'value': {'string[]': []}, 'verif': 22222222}]}, 'verif': 22222222}]}, 'verif': 22222222}]
答案1
得分: 1
你可以使用递归来查找具有指定键的字典。
def get(o, k):
if isinstance(o, list):
for x in o:
if res := get(x, k):
return res
elif o['key'] == k:
return o
elif nxt := o.get('value', {}).get('instance[]'):
return get(nxt, k)
o = get(test, 'requires')
if o:
o['value']['string[]'] += "aaaa", "bbb"
print(test) # test now changed
(Note: I've provided the translated code as requested.)
英文:
You could use recursion to find the dict with the specified key.
def get(o, k):
if isinstance(o, list):
for x in o:
if res := get(x, k):
return res
elif o['key'] == k:
return o
elif nxt := o.get('value', {}).get('instance[]'):
return get(nxt, k)
o = get(test, 'requires')
if o:
o['value']['string[]'] += "aaaa", "bbb"
print(test) # test now changed
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