类似的代码。一个有效,另一个无效?为什么?

huangapple go评论55阅读模式
英文:

Similar code. One works another not? Why?

问题

无法找到问题。请帮忙。
有2个页面。第一个完美运行,表(AnalysisGraph)也在工作。
第二个不行。数据没有更改,传递给(AnalysisGraph或ShowGraph - ShowGraph与AnalysisGraph相同,只是没有功能的)。为什么在第一个页面中,我可以在saveAnalysis中更改数据并传递给AnalysisGraph,但在第二个页面中无法更改数据?

对于长代码感到抱歉。

第一页

@State var analizaId = ""
@State var finance = 0.0
@State var value = 0.0
@State var growth = 0.0

.sheet(isPresented: $newAnalysis) {
    AnalysisGraph(clearAnalysis: clear, analizaId: analizaId, finance: finance, value: value, growth: growth, name: name, notes: notes)
}

private func saveAnalysis(){
    finance = model.financeCondition()
    growth = model.growthCondition()
    value = model.valueCondition()
    analizaId = model.modelId
}

第二页

@State var analizaId = ""
@State var finance = 0.0
@State var value = 0.0
@State var growth = 0.0

.sheet(isPresented: $showAnalysisGraph) {
    ShowGraph(analizaId: analizaId, finance: finance, value: value, growth: growth, name: name, notes: notes)
}

private func setDataToGraph(){
    if let idAnalysis = selected{
        for (_, item) in analysisList.enumerated(){
            if let idItem = item.id{
                if idItem == idAnalysis{
                    thisAnaliza = item
                }
            }
        }
    }
    if let showAnaliza = thisAnaliza, let idOptionalAnaliza = selected, let idAnaliza = idOptionalAnaliza{
        print("idAnaliza: \(idAnaliza)")
        analizaId = idAnaliza
        finance = showAnaliza.financeAnalysis
        growth = showAnaliza.growthAnalysis
        value = showAnaliza.valueAnalysis
        name = showAnaliza.name ?? "No Name"
        notes = showAnaliza.notes ?? "No notes"
        print("analizaId: \(analizaId)")
        print("\(finance)")
        print("\(value)")
        print("\(growth)")
        print(name)
        print(notes)
        showAnalysisGraph.toggle()
    }
}
英文:

I cannot find the issue. Please help.
There are 2 pages. First is working perfectly and the sheet (AnalysisGraph) is working
On second is not. Data is not changed and empty data is passed to (AnalysisGraph or ShowGraph - ShowGraph is like AnalysisGraph only without function)
Why in 1 page I can change data in saveAnalysis and passed that to AnalysisGraph but I cannot change data in 2 page?

Sorry for long code

1 page

@State var analizaId = ""
@State var finance = 0.0
@State var value = 0.0
@State var growth = 0.0

                .sheet(isPresented: $newAnalysis) {
                    AnalysisGraph(clearAnalysis: clear, analizaId: analizaId, finance: finance, value: value, growth: growth, name: name, notes: notes)
                }
            }

 private func saveAnalysis(){
        finance = model.financeCondition()
        growth = model.growthCondition()
        value = model.valueCondition()

        analizaId = model.modelId
 }

2 page

@State var analizaId = ""
@State var finance = 0.0
@State var value = 0.0
@State var growth = 0.0

           .sheet(isPresented: $showAnalysisGraph) {
                ShowGraph(analizaId: analizaId, finance:     finance, value: value, growth: growth, name: name, notes: notes)

}

private func setDataToGraph(){
    if let idAnalysis = selected{
        for (_, item) in analysisList.enumerated(){
            if let idItem = item.id{
                if idItem == idAnalysis{
                    thisAnaliza = item
                }
            }
        }
    }
    if let showAnaliza = thisAnaliza, let idOptionalAnaliza =    selected, let idAnaliza = idOptionalAnaliza{
        print("idAnaliza: \(idAnaliza)")
        analizaId = idAnaliza
        finance = showAnaliza.financeAnalysis
        growth = showAnaliza.growthAnalysis
        value = showAnaliza.valueAnalysis
        name = showAnaliza.name ?? "No Name"
        notes = showAnaliza.notes ?? "No notes"
        print("analizaId: \(analizaId)")
        print("\(finance)")
        print("\(value)")
        print("\(growth)")
        print(name)
        print(notes)
        showAnalysisGraph.toggle()
    }
}

答案1

得分: 1

在第2页,仅当状态被设置时才会调用body,前提是这些先前的状态已在body内部被读取。在sheet内部不计算。

尝试用1个可选的项目结构state(封装您的4个变量)替换这4个状态,并使用sheet(item:)。

英文:

In 2 page, body is only called when states are set if those previous states have been read inside body. Inside sheet doesn't count.

Try replacing the 4 states with 1 optional item struct state (encapsulating your 4 vars) and use sheet(item:).

huangapple
  • 本文由 发表于 2023年6月2日 08:11:22
  • 转载请务必保留本文链接:https://go.coder-hub.com/76386436.html
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