英文:
Is there a way to merge two mutated dataframes together?
问题
所以，我基本上有两个数据框，从一个名为'original_data'的单一数据框突变而来：
我在'original_data'上使用了mutate函数，以保留仅<= 600秒的值，所有其他值将返回为NA，这存储在'new_data_one'中。
然后我再次在'original_data'上使用mutate函数，以保留单个值> 600，所有其他值将返回为NA，这存储在'new_data_two'中。
这两个数据框都保留了它们的结构，所以类似这样：
'original_data'
1 2 3 4 5R1 80 98 150 599 650R2 90 95 254 725 905R3 93 96 540 650 780
'new_data_one'
1 2 3 4 5R1 80 98 150 599 NAR2 90 95 254 NA NAR3 93 96 540 NA NA
'new_data_two'
1 2 3 4 5R1 NA NA NA NA 650R2 NA NA NA 725 NAR3 NA NA NA 650 NA
我如何合并这两个突变的数据框（'new_data_one'和'new_data_two'），以便获得类似下面的输出（基本上保留相同的列/行结构）？
'desired_merged_dataframe'
1 2 3 4 5R1 80 98 150 599 650R2 90 95 254 725 NAR3 93 96 540 650 NA
英文:
so I basically have two dataframes mutated from a single dataframe 'original_data':
I used the mutate function on 'original data' to keep only values <= 600 seconds, all the other values would return as NA, this is stored in 'new_data_one'.
I then used the mutate function on 'original data' again to keep a single value >600, all the other values would return as NA, this is stored in 'new_data_two'.
Both of these dataframe retained their structure, so something like this:
'original_data'
1 2 3 4 5R1 80 98 150 599 650R2 90 95 254 725 905R3 93 96 540 650 780
'new_data_one'
1 2 3 4 5R1 80 98 150 599 NAR2 90 95 254 NA NAR3 93 96 540 NA NA
'new_data_two'
1 2 3 4 5R1 NA NA NA NA 650R2 NA NA NA 725 NAR3 NA NA NA 650 NA
How do I merge the two mutated dataframes ('new_data_one' and 'new_data_two'), so I get an output of something like this (that essentially retains the same col/row structures)?
'desired_merged_dataframe'
1 2 3 4 5R1 80 98 150 599 650R2 90 95 254 725 NAR3 93 96 540 650 NA
答案1
得分: 4
replace(df1, is.na(df1), df2[is.na(df1)])X1 X2 X3 X4 X5R1 80 98 150 599 650R2 90 95 254 725 NAR3 93 96 540 650 NA
library(tidyverse)map2_df(df1, df2, coalesce)# 一个 tibble: 3 × 5X1 X2 X3 X4 X5<int> <int> <int> <int> <int>1 80 98 150 599 6502 90 95 254 725 NA3 93 96 540 650 NA
英文:
replace(df1, is.na(df1), df2[is.na(df1)])X1 X2 X3 X4 X5R1 80 98 150 599 650R2 90 95 254 725 NAR3 93 96 540 650 NA
library(tidyverse)map2_df(df1, df2, coalesce)# A tibble: 3 × 5X1 X2 X3 X4 X5<int> <int> <int> <int> <int>1 80 98 150 599 6502 90 95 254 725 NA3 93 96 540 650 NA
答案2
得分: 0
这里是一个dplyr的解决方案：
library(dplyr)new_data_one %>%mutate(across(everything(), ~ coalesce(., new_data_two[[cur_column()]])))X1 X2 X3 X4 X5R1 80 98 150 599 650R2 90 95 254 725 NAR3 93 96 540 650 NA
英文:
Here is a dplyr solution:
library(dplyr)new_data_one %>%mutate(across(everything(), ~ coalesce(., new_data_two[[cur_column()]])))X1 X2 X3 X4 X5R1 80 98 150 599 650R2 90 95 254 725 NAR3 93 96 540 650 NA
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