英文:
How can I randomize a list of integers 1 to X in CircuitPython without duplicates?
问题
我正在创建一个 CircuitPython 项目，代码编译正常，但它不按照我的意图运行。我有一个循环，它应该生成一个不重复的整数列表，从1到X，随机排序。它确实这样做，除了1和2总是以某种奇怪的原因复制在其中。因为这是在 CircuitPython 中，我不能使用 random.sample，所以这是一个简单的代码，但它仍然不起作用。
编辑：我需要列表最终变成字符串列表而不是整数列表。我没有清楚表达这一点。
station = 20
songs = []
loop = True
while loop == True:
r=random.randint(1, station)
if r not in songs:
songs.append(str(r))
if len(songs) == station:
loop = False
输出: ['14', '3', '11', '20', '10', '17', '9', '5', '19', '1', '6', '18', '15', '8', '2', '4', '7', '12', '16', '13']
在这种情况下，2不会重复出现，但1会。我只想要一个精确的1到X的列表，随机排序，没有重复项。
英文:
I am creating a circuit python project and the code compiles fine but it isn't working the way I intend. This loop that I have is supposed to generate a non repeating list of integers 1 to X in a random order. It does that except 1 and 2 are always copied in there for some odd reason. Because this is in circuit python, I cannot use random.sample so thats why this is simple code but it still doesn't work.
Edit: I do need the list to end up as a list of strings instead of a list of Integers. I failed to make that clear.
station = 20
songs = []
loop = True
while loop == True:
r=random.randint(1, station)
if r not in songs:
songs.append(str(r))
if len(songs) == station:
loop = False
Output: ['14', '3', '11', '20', '10', '17', '9', '5', '19', '17', '1', '6', '18', '1', '9', '15', '6', '11', '14', '8', '2']
In this case 2 isn't in there twice but 1 is. I just want an exact list of 1 - X randomized with no duplicates.
答案1
得分: 1
将字符串放入列表中，但将其与整数进行比较。立即将其转换为字符串，以便使用一致的类型。
while len(songs) < station:
r = str(random.randint(1, station))
if r not in songs:
songs.append(r)
英文:
You're putting strings in the list but comparing them with ints. Convert it to a string immediately so you use consistent types.
while len(songs) < station:
r = str(random.randint(1, station))
if r not in songs:
songs.append(r)
答案2
得分: 0
随机洗牌不难编写，是解决这个问题的较好方法之一：
import random
station = 20
def shuffle(lst):
for i in range(len(lst)):
j = random.randrange(0, len(lst))
lst[i], lst[j] = lst[j], lst[i]
songs = list(range(1, station+1))
print(songs)
shuffle(songs)
print(songs)
后续
好的，让我们进行两个小的修改，以改善随机性。 在这种特殊情况下，差异微不足道，但在研究情境中，这可能很重要：
import random
station = 20
def shuffle(lst):
for i in range(len(lst)-1):
j = random.randrange(i, len(lst))
lst[i], lst[j] = lst[j], lst[i]
songs = list(range(1, station+1))
print(songs)
shuffle(songs)
print(songs)
英文:
Random shuffle is not hard to write, and is one of the better approaches to this problem:
import random
station = 20
def shuffle(lst):
for i in range(len(lst)):
j = random.randrange(0,len(lst))
lst[i],lst[j] = lst[j],lst[i]
songs = list(range(1,station+1))
print(songs)
shuffle(songs)
print(songs)
Followup
OK, let's make two small modifications that improve the randomness. In this particular case, the difference is insignificant, but in a research situation, it could be important.
import random
station = 20
def shuffle(lst):
for i in range(len(lst)-1):
j = random.randrange(i,len(lst))
lst[i],lst[j] = lst[j],lst[i]
songs = list(range(1,station+1))
print(songs)
shuffle(songs)
print(songs)
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论