英文:
iOS URL settings shortcut doesn't launch into settings app
问题
我想将用户引导到设置页面，并打开“未知来电静音”开关。谷歌搜索结果显示以下是用于此目的的URL：
UIApplication.shared.open(URL(string: "prefs:root=Phone&path=SILENCE_CALLS")!, options: [:])
然而，这并不起作用，它不会启动任何内容。这是否是正确的URL，或者苹果可能已禁用此功能（我正在使用iOS 16.4.1）？
英文:
(Yes I know using this url will result in Apple rejecting the app from App Store submission, however the intended use is not for an app released to the App Store).
I want to launch the user into the settings page with the silence unknown caller's switch, google results says this is the url to use for that:
UIApplication.shared.open(URL(string: "prefs:root=Phone&path=SILENCE_CALLS")!, options: [:])
However this doesn't work, it doesn't launch anything.
Is this the correct url, or might Apple have disabled this from functioning (I'm trying with iOS 16.4.1)
答案1
得分: 0
从iOS 10及更高版本开始，代码已更改，请使用以下代码。
您需要将 prefs: 更改为 App-Prefs:
UIApplication *application = [UIApplication sharedApplication];
NSURL *URL = [NSURL URLWithString:@"App-Prefs:root=Phone&path=SILENCE_CALLS"];
[application openURL:URL options:@{} completionHandler:^(BOOL success) {
if (success) {
NSLog(@"已打开URL");
}
}];
英文:
From iOS 10+ versions code has changed, use below code.
You need to change prefs: to App-Prefs:
UIApplication *application = [UIApplication sharedApplication];
NSURL *URL = [NSURL URLWithString:@"App-Prefs:root=Phone&path=SILENCE_CALLS"];
[application openURL:URL options:@{} completionHandler:^(BOOL success) {
if (success) {
NSLog(@"Opened url");
}
}];
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