英文:
Area of each cell covered by polygons
问题
有没有一种方法/函数可以计算由多边形覆盖的每个栅格单元的比例？这些多边形通常比单个单元格大，我正在处理的景观相当大。我希望能够在不将栅格转换为单元格多边形和执行st_union/st_join的情况下完成这个任务，但我不确定是否可能。
我希望的输出是一个栅格，其中的单元格值显示每个单元格被多边形图层覆盖的比例。
英文:
Is there a way/function to calculate the proportion of each raster cell covered by a polygon? The polygons are usually larger than single cells and the landscape I'm working on is pretty big. I'll like to do it without converting the raster into cell-polygons and st_union/st_join, but I'm not sure if it's possible.
The output I'm looking for is a raster with cell values showing the proportion of each cell covered by the polygons layer.
答案1
得分: 1
谢谢评论。
最后，应用于多边形图层的terra::rasterize()函数，使用cover = T参数，正好符合我的要求...而且速度超快。
我能够将所有操作保持在“栅格方面”，避免了将栅格模板矢量化并进行相交/空间连接的更强烈处理。
英文:
Thanks for the comments.
At the end the terra::rasterize() function with the cover = T parameter applied on the polygons layer does exactly what I was looking for... and it's super fast.
I was able to keep it all on the "raster side" and avoid the more intense processing of vectorizing the raster template and doing intersects/spatial joins.
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