XPath that returns true when at least one element matches

Let's assume we have the following XML response:

<People>
    <Person>
        <Age>29</Age>
    </Person>
    <Person>
        <Age>25</Age>
    </Person>
    <Person>
        <Age>18</Age>
    </Person>
    <Person>
        <Age>45</Age>
    </Person>
</People>

I want an xpath 2.0 expression that will return true if there is at least one person with age between 18 and 22.

My current expression is:

boolean(//*:Person[xs:integer(substring(//*[local-name() = 'Age']/text(), 2)) >= 18 and 22 >= xs:integer(substring(//*[local-name() = 'Age']/text(), 2))])

But this expression is not recursive so it produces the following error:

>A sequence of more than one item is not allowed as the first argument of substring() ("29", "25", ...)

Any idea as to how I can achieve what I need?

In XPath 2.0 this is exists(//Person[Age = (18 to 22)])

This XPath,

boolean(/People/Person[Age > 18][Age < 22])

will return true iff at least one Person has an age between 18 and 22, exclusive.

Notes:

• Be sure to use < for < if this XPath is embedded in XML/XSLT.

• Use >= and/or <= for inclusive endpoints.

• There is no reason to use local-name() and *: unless you are trying to defeat namespaces, which

  1. are not in play here anyway, but
  2. can and should be accommodated, not defeated.

here's a twisted one that uses count and translate

count(//Age[translate(translate(., "1", "X"),"89","YY") = "XY" or .="22" or translate(translate(., "2", "X"),"01","YY") = "XY"]) > 0

22 is an special case since translate turns it into XX