英文:
alternative to use eval python eval-used / W0123
问题
You can achieve the same result without using eval by directly accessing the values from the dictionaries and executing functions like this:
import os
d1 = {
"a": "test"
}
cmd_dict = {
"cmd1": d1['a'],
"cmd2": os.getcwd()
}
value = cmd_dict['cmd1']
print(value)
This eliminates the need for eval and should resolve the pylint error W0123.
英文:
d1 = {
"a": "test"
}
cmd_dict = {
"cmd1": "d1['a']",
"cmd2 : "os.getcwd()"
}
value = eval(md_dict['cmd1])
print(value)
Not i will get the value as test.
I am getting pylint error W0123 becasue i am using eval.
is there any way to perform the same without using eval.
答案1
得分: 1
将函数放入你的字典中，然后你可以像调用任何其他函数一样调用它们。不需要使用eval()：
import os
d1 = {}
cmd_dict = {
"cmd1": lambda: d1['a'],
"cmd2": os.getcwd,
}
d1['a'] = 'test'
value = cmd_dict['cmd1']()
print(value) # test
请注意，lambda 创建了一个小的匿名函数，当调用它时，它将评估并返回d1['a']；延迟评估（你不需要使用eval()来完成）是为什么它返回test，即使该值在创建cmd_dict之后设置在d1中的原因。
英文:
Put functions in your dictionary, and you can simply call them like any other function. No eval() needed:
import os
d1 = {}
cmd_dict = {
"cmd1": lambda: d1['a'],
"cmd2" : os.getcwd,
}
d1['a'] = 'test'
value = cmd_dict['cmd1']()
print(value) # test
Note that lambda creates a small anonymous function that will evaluate and return d1['a'] when it's called; the delayed evaluation (which, again, you do not need eval() to do) is why it returns test even though that value is set in d1 after cmd_dict has been created.
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