英文:
Regex statement that matches an optional character into the same group
问题
正则表达式沙盒：
https://regex101.com/r/nAhuot/1
我需要将浮点数与整数分组。关键词是相同的组。我可以匹配小数点后的内容，如下所示：
(\d+)?(.)?(\d+)[ \t]+NUM(\d) <--- 用于匹配小数点后的正则表达式
(\d+)[ \t]+NUM(\d) <---- 用于匹配小数点之前的正则表达式
这是文本内容：
1.5707963267949 NUM0 ;
0 NUM1 ;
0 NUM2 ;
0 NUM3 ;
0 NUM4 ;
0 NUM5 ;
期望的结果是在正则表达式内有2个组，看起来像这样：
(1.5707963267949,NUM0),(0,NUM1),(0,NUM2),(0,NUM3),(0,NUM4),(0,NUM5)
我的解决方案创建了多个组，如何将它们合并成一个组？
英文:
Regex sandbox:
https://regex101.com/r/nAhuot/1
I need to group floats with ints. The keyword here is the same group. I can match beyond the decimal point like so:
(\d+)?(.)?(\d+)[ \t]+NUM(\d) <--- Regex to match beyond the decimal
(\d+)[ \t]+NUM(\d) <---- Regex to match up to the decimal
This is the text:
1.5707963267949 NUM0 ;
0 NUM1 ;
0 NUM2 ;
0 NUM3 ;
0 NUM4 ;
0 NUM5 ;
The expected result is to have 2 groups within the regex, look like this:
(1.5707963267949,NUM0),(0,NUM1),(0,NUM2),(0,NUM3),(0,NUM4),(0,NUM5)
My solution makes multiple groups, how can I make it to group into only one group?
答案1
得分: 1
不确定为什么答案从评论中删除了，但这是有效的代码：
((?:\-)?\d+(?:\.\d+)?)[ \t]+NUM(\d+)
感谢解决问题的用户，但已遗失他的用户名。
英文:
Unsure why the answer was wiped from the comments, but this is what worked:
((?:\-)?\d+(?:\.\d+)?)[ \t]+NUM(\d+)
Thank you to the user who solved it, lost his username
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