返回基于级别(p2)的父位置的查询。

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英文:

Write a query to return parent location base on level (p2)

问题

在我的之前的问题中,我可以解决如何获取位置层次结构的问题。但是,当尝试与系统集成时,似乎出现了另一个问题。

所以我有两个表格,如下:

位置(约20,000条记录)

id 名称 是否激活 level1 level2 level3 level4
1 A true A null null null
2 A > B true A B null null
3 A > B > C true A B C null
4 A > B > C > D true A B C D
5 X true X null null null

日志(约5百万条记录)

id 名称 location_id
1 日志001 3
2 日志002 5

所以目标是我想获取只有日志的位置层次结构。
问题是当我尝试与日志表连接时,性能存在问题。查询似乎需要超过10分钟。

以下是我的查询样式demo
我尝试了这个查询

SELECT *
FROM   location
START WITH id IN (SELECT DISTINCT location_id FROM log_response)
CONNECT BY PRIOR name
           = name || '>' || COALESCE(PRIOR level4, PRIOR level3, PRIOR level2)
ORDER BY NAME

或者

WITH cte(location_id) AS (
     SELECT DISTINCT location_id FROM log_response
)
SELECT *
FROM   location
START WITH id IN (SELECT location_id FROM cte)
CONNECT BY PRIOR name
           = name || '>' || COALESCE(PRIOR level4, PRIOR level3, PRIOR level2)
ORDER BY NAME

附注:在上面的示例中,查询的期望结果应该返回具有id在(1、2、3、5)的位置。

id 名称 是否激活 level1 level2 level3 level4
1 A true A null null null
2 A > B true A B null null
3 A > B > C true A B C null
5 X true X null null null

非常感谢!

英文:

At the my previous question, I can solve how to fetch the location hierarchy. But It seems I have another issue when try to integrate with the system

so I have 2 tables like

location (~20k records)

id Name is_active level1 level2 level3 level4
1 A true A null null null
2 A>B true A B null null
3 A>B>C true A B C null
4 A>B>C>D true A B C D
5 X true X null null null

log (~5m records)

id Name location_id
1 log 001 3
2 log 002 5

So the goal is I would like to fetch the location hierarchy which has log only.
The problem is when I try to join with the log table, It has a performance issue. The query seems to take 10+ minutes

Here is how my query looks like demo
I'm trying this query

SELECT *
FROM   location
START WITH id IN (SELECT DISTINCT location_id FROM log_response)
CONNECT BY PRIOR name
           = name || '>' || COALESCE(PRIOR level4, PRIOR level3, PRIOR level2)
ORDER BY NAME

or

WITH cte(location_id) AS (
     SELECT DISTINCT location_id FROM log_response
)
SELECT *
FROM   location
START WITH id IN (SELECT location_id FROM cte)
CONNECT BY PRIOR name
           = name || '>' || COALESCE(PRIOR level4, PRIOR level3, PRIOR level2)
ORDER BY NAME

p/s The expectation of the query on the above example should return the location have id in (1,2,3,5)

id Name is_active level1 level2 level3 level4
1 A true A null null null
2 A>B true A B null null
3 A>B>C true A B C null
5 X true X null null null

Thank you very much!

答案1

得分: 0

你可以使用 EXISTS(而不是 INDISTINCT):

SELECT *
FROM location l
START WITH EXISTS(SELECT 1 FROM log WHERE location_id = l.id)
CONNECT BY name = SUBSTR(PRIOR name, 1, INSTR(PRIOR name, '>', -1) - 1)

对于示例数据:

CREATE TABLE location (id, Name, is_active, level1, level2, level3, level4) AS
SELECT 1, 'A', 'true', 'A', null, null, null FROM DUAL UNION ALL
SELECT 2, 'A>B', 'true', 'A', 'B', null, null FROM DUAL UNION ALL
SELECT 3, 'A>B>C', 'true', 'A', 'B', 'C', null FROM DUAL UNION ALL
SELECT 4, 'A>B>C>D', 'true', 'A', 'B', 'C', 'D' FROM DUAL UNION ALL
SELECT 5, 'X', 'true', 'X', null, null, null FROM DUAL;

CREATE TABLE log (id, Name, location_id) AS
SELECT 1, 'log 001', 3 FROM DUAL UNION ALL
SELECT 2, 'log 002', 5 FROM DUAL;

输出:

ID NAME IS_ACTIVE LEVEL1 LEVEL2 LEVEL3 LEVEL4
3 A>B>C true A B C null
2 A>B true A B null null
1 A true A null null null
5 X true X null null null

或:

SELECT DISTINCT *
FROM location l
START WITH EXISTS(SELECT 1 FROM log WHERE location_id = l.id)
CONNECT BY 
       PRIOR level1 = level1
AND    (  (   level2 IS NULL AND level3 IS NULL AND level4 IS NULL
          AND PRIOR level2 IS NOT NULL AND PRIOR level3 IS NULL AND PRIOR level4 IS NULL
          )
          OR (   PRIOR level2 = level2
             AND ( (   level3 IS NULL AND level4 IS NULL
                   AND PRIOR level3 IS NOT NULL AND PRIOR level4 IS NULL
                   )
                 OR (   PRIOR level3 = level3
                    AND level4 IS NULL AND PRIOR level4 IS NOT NULL
                    )
                 )
              )
      )

fiddle

英文:

You can use EXISTS (rather than IN and DISTINCT):

SELECT *
FROM   location l
START WITH EXISTS(SELECT 1 FROM log WHERE location_id = l.id)
CONNECT BY name = SUBSTR(PRIOR name, 1, INSTR(PRIOR name, '>', -1) - 1)

Which, for the sample data:

CREATE TABLE location (id, Name, is_active, level1, level2, level3, level4) AS
SELECT 1, 'A',       'true', 'A', null, null, null FROM DUAL UNION ALL
SELECT 2, 'A>B',     'true', 'A', 'B',  null, null FROM DUAL UNION ALL
SELECT 3, 'A>B>C',   'true', 'A', 'B',  'C',  null FROM DUAL UNION ALL
SELECT 4, 'A>B>C>D', 'true', 'A', 'B',  'C',  'D'  FROM DUAL UNION ALL
SELECT 5, 'X',       'true', 'X', null, null, null FROM DUAL;

CREATE TABLE log (id, Name, location_id) AS
SELECT 1, 'log 001', 3 FROM DUAL UNION ALL
SELECT 2, 'log 002', 5 FROM DUAL;

Outputs:

ID NAME IS_ACTIVE LEVEL1 LEVEL2 LEVEL3 LEVEL4
3 A>B>C true A B C null
2 A>B true A B null null
1 A true A null null null
5 X true X null null null

Or:

SELECT DISTINCT *
FROM   location l
START WITH EXISTS(SELECT 1 FROM log WHERE location_id = l.id)
CONNECT BY 
       PRIOR level1 = level1
AND    (  (   level2 IS NULL AND level3 IS NULL AND level4 IS NULL
          AND PRIOR level2 IS NOT NULL AND PRIOR level3 IS NULL AND PRIOR level4 IS NULL
          )
          OR (   PRIOR level2 = level2
             AND ( (   level3 IS NULL AND level4 IS NULL
                   AND PRIOR level3 IS NOT NULL AND PRIOR level4 IS NULL
                   )
                 OR (   PRIOR level3 = level3
                    AND level4 IS NULL AND PRIOR level4 IS NOT NULL
                    )
                 )
              )
      )

fiddle

huangapple
  • 本文由 发表于 2023年5月30日 01:07:37
  • 转载请务必保留本文链接:https://go.coder-hub.com/76359166.html
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