禁用路由基于条件

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英文:

How to disable a route based on a condition

问题

我需要使菜单项仍然存在于子菜单中,但在某种条件下变为禁用状态,条件始终相同。在上面的代码中,对于具有null值作为element的任何路由,我需要禁用它。是否有一种方法可以做到这一点,而不是删除具有null值作为element的路由?

英文:

I have a route set up for a menu

import React from 'react';
import { Route, Routes, Navigate } from 'react-router-dom';
import { SalesOverviewNewPage } from "./inner-components";

export const DashboardPage = (props) => {
  return (
    <div className="flexRow full p-0 m-0">
      <div className='full-flex flexCol width100 p-0 m-0'>
        <Routes>
          <Route path="/" element={<Navigate replace to="sales-overview-new" />} />
          <Route path="/sales-overview-new" element={<SalesOverviewNewPage />} />
          <Route path="/devices-overview" element={null} />
          <Route path="/perfomance" element={null} />
          <Route path="/sales-datewise" element={null} />
          <Route path="/top-items-more" element={null} />
        </Routes>
      </div>
    </div>
  )
}

i need to make the menu items which doesn't have a component available to be still present in the submenu but to become disabled sort of based on a condition which isa always same.In the above code for which ever route that has null value as element i need to disable it. Is there a way to do this instead of removing the routes which has null value as elements.

答案1

得分: 0

以下是已翻译的内容:

创建一个路由对象,并在DashboardPage和Navigation两个地方使用它是一个简单的解决方案。

创建路由对象,如下所示:

const routes = [
  {
    text: '',   //这将是链接文本
    component: <Navigate replace to="sales-overview-new" />,   // 或者保持为null
    path: '/',
  },
  {
    text: '销售概览新版',   //这将是链接文本
    component: <SalesOverviewNewPage />,   // 或者保持为null
    path: '/sales-overview-new',
  },
  {
    text: '销售概览新版',   //这将是链接文本
    component: null,   // 或者保持为null
    path: '/sales-overview-new',
  }
]

然后,在DashboardPage中导入这些路由,并创建如下所示的Routes:

<Routes>
  routes.map(route => (
    // 我使用routes.path作为键,因为大多数情况下它将是唯一的,您可以使用索引或其他任何值。
    <Route key={route.path} path={route.path} element={route.component} />
  ));
</Routes>

接下来,在呈现链接时导入并使用相同的路由对象:

<nav>
  routes.map(route => (
    route.component !== null ? 
      // 正常链接  : 
      // 禁用链接
  ));
</nav>

根据您的需求修改和样式化禁用链接和正常链接。

英文:

A simple solution is to create a route object and use it in both places DashboardPage and Navigation.

Create an object of your routes like below:

const routes = [
  {
    text: &#39;&#39;,   //this will be the link text
    component: &lt;Navigate replace to=&quot;sales-overview-new&quot; /&gt;,   // Or keep this null
    path: &#39;/&#39;,
  },
  {
    text: &#39;Sales Overview New&#39;,   //this will be the link text
    component: &lt;SalesOverviewNewPage /&gt;,   // Or keep this null
    path: &#39;/sales-overview-new&#39;,
  },
  {
    text: &#39;Sales Overview New&#39;,   //this will be the link text
    component: null,   // Or keep this null
    path: &#39;/sales-overview-new&#39;,
  }
]

Next, import these routes in the DashboardPage and create Routes like this:

&lt;Routes&gt;
  routes.map(route =&gt; (
    //I am using the key as routes.path as most of the times it will be unique, you can use index or any other value.
    &lt;Route key={routes.path} path={routes.path} element={routes.component} /&gt;
  ));
&lt;/Routes&gt;

Then, import and use the same routes object while rendering the links:

&lt;nav&gt;
  routes.map(route =&gt; (
    route.component !== null ? 
      //Normal link  : 
      //Disabled link
  ));
&lt;/nav&gt;

Modify and style disabled link and normal links as per your requirements.

huangapple
  • 本文由 发表于 2023年5月29日 19:46:10
  • 转载请务必保留本文链接:https://go.coder-hub.com/76357081.html
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