英文:
How can I cast a JSON object to a TypeScript class instance without any external library?
问题
我正在尝试将一个JSON对象进行类型转换，示例如下：
class Person {
constructor(
public firstName,
public lastName
) {}
function getName() {
return this.firstName + “ “ + this.lastName;
}
}
目标是解析如下所示的JSON：
{
firstName: “Max“,
lastName: “Mustermann“
}
以便将其转换为上述类的实例，以访问所有属性和方法。
是否有一种简单的方法可以创建一个函数，使这种类型的JSON和类的转换功能成为可能？
同时，嵌套对象也应该是可能的。
我可以为每个不同的类编写一个工厂方法，但应该有一种更好的方法来获得这样的功能。
英文:
I am trying to cast a JSON object like the following example:
class Person {
constructor(
public firstName,
public lastName
) {}
function getName() {
return this.firstName + “ “ + this.lastName;
}
}
The goal is to parse the JSON which looks like this:
{
firstName: “Max“,
lastName: “Mustermann“
}
to an instance of the above class to access all properties and methods.
Is there an easy way to create a function which can make such a functionality possible for such type of JSONs/classes?
Also nested objects should be possible.
I can write a factory method for every different class but there should be an better way to get such functionality.
答案1
得分: 1
创建你的类如下，注意构造函数：
class Person {
public firstName: string;
public lastName: string;
public constructor(init?: Partial<Person>) {
Object.assign(this, init);
}
function getName() {
return this.firstName + " " + this.lastName;
}
}
将 JSON 传递给这个构造函数：
let person = new Person({ firstName: "A", lastName: "B" });
console.log(person);
英文:
Use Object.assign
Create your class like this, observe the constructor
class Person {
public firstName: string;
public lastName: string;
public constructor(init?: Partial<Person>) {
Object.assign(this, init);
}
function getName() {
return this.firstName + “ “ + this.lastName;
}
}
Pass the json into this constructor
let person = new Person({firstName: "A", lastName: "B" });
console.log(person);
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