选择不同行中的共同因素。

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英文:

Selecting common factors in different rows

问题

select
   group,
   from_when,
   array_agg(distinct id),
   array_agg(distinct favourite_colour),
   array_agg(distinct concat(id, '-', favourite_colour, '-', from_when)) as connection
from database_example
group by
   group,
   from_when
having sum(points) > 70
英文:

I have a database which looks like below. It lists different people's favourite colours when they were children or after they became adults. It groups people when they have common favourite colour. For example, ID number 1 and 2 are grouped together as they have red in common. In such case, the second row (ID number 2, group b, favourite colour blue -)also is grouped as b since it is the same ID/person as row 3.

id group favourite_colour from_when points
1 b red child 30
2 b blue child 50
2 b red adult 50
3 c white adult 22
4 c white adult 24

Based on this, I want to create such a query as follwing:

select
   group,
   from_when,
   array_agg(distinct id),
   array_agg(distinct favourite_colour)

from database_example

group by
   group,
   from_when

having sum(points) > 70

The objectives is to group the people who belong to the same group by 'from_when' column and filter by summed points more than 70.

With the given example, this should return:

group from_when id favourite_colour
b child 1,2 red,blue

I want to add one more column in the result which can show how ID 1 and 2 are grouped together because, if we only look at the current query result, it looks like they don't belong to the same group with their different favourite colours. However, in reality, ID 1 and 2 are grouped together as ID 1 (child) and ID 2 (adult) which currently is not shown in the result share the same favourite colour.

As an example, an additional column (connection) like below is the type of results I'd like to include.

group from_when id favourite_colour connection
b child 1,2 red,blue 1-red-child,2-red-adult

How could this be achieved?

答案1

得分: 1

以下是已翻译的内容:

可以使用通用表达式(CTE)来完成这个任务。

第一个CTE是查询,我们按groupfrom_when对数据进行分组,而第二个CTE用于按groupfavourite_colour分组并遵循相同的条件获取数据,然后通过一些连接操作获取期望的输出:

with cte_from_when as (
  select group_, from_when,
        array_agg(distinct id) as ids,
        array_agg(distinct favourite_colour) as colors
  from mytable
  group by group_, from_when
  having sum(points) > 70
),
cte_favourite_colour as (
  select group_, favourite_colour
  from mytable
  group by group_, favourite_colour
  having sum(points) > 70
)
select cw.group_, cw.from_when, min(ids) as ids, min(cw.colors) as favourite_colour, array_agg(t.id || '-' || cc.favourite_colour || '-' || t.from_when) as connection
from cte_from_when cw
inner join mytable t on t.group_ = cw.group_ and t.favourite_colour = ANY(colors)
inner join cte_favourite_colour cc on cc.group_ = t.group_ and cc.favourite_colour = t.favourite_colour
group by cw.group_, cw.from_when

在PostgreSQL上测试通过,请查看此处的演示

英文:

You can do it using CTEs.

First CTE is the query where we get data grouped by group and from_when, while second CTE is used to get data grouped by group and favourite_colour and respected same condition, then Using some joins we get the Expected output :

with cte_from_when as (
  select group_, from_when,
        array_agg(distinct id) as ids,
        array_agg(distinct favourite_colour) as colors
  from mytable
  group by group_, from_when
  having sum(points) > 70
),
cte_favourite_colour as (
  select group_, favourite_colour
  from mytable
  group by group_, favourite_colour
  having sum(points) > 70
)
select cw.group_, cw.from_when, min(ids) as ids, min(cw.colors) as favourite_colour, array_agg(t.id || '-' || cc.favourite_colour || '-' || t.from_when) as connection
from cte_from_when cw
inner join mytable t on t.group_ = cw.group_ and t.favourite_colour = ANY(colors)
inner join cte_favourite_colour cc on cc.group_ = t.group_ and cc.favourite_colour = t.favourite_colour
group by cw.group_, cw.from_when

Tested on Postgresql, check demo here

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  • 本文由 发表于 2023年5月29日 16:20:48
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