英文:
Using yq to replace name of docker image
问题
我正在使用GitHub Actions创建新的镜像并将其推送到镜像仓库。
这部分代码可以不翻译：
- name: Build the Docker image
run: docker build . --file Dockerfile --tag ${{secrets.DOCKER_USER}}/book:$GITHUB_SHA
这个方法运行得很好。现在，我需要替换镜像的值。所以我考虑使用yq：
apiVersion: apps/v1
kind: Deployment
spec:
template:
spec:
containers:
- image: xxxxx/book:main
- name: 替换镜像
run: yq -i e '.spec.template.spec.containers.image |= ${{secrets.DOCKER_USER}}/guestbook:$GITHUB_SHA' argo/deployment.yaml
但是出现了这个错误：“错误：1:43：无效的输入文本“xxxx/book:...”
错误：进程以退出码1完成。”
我应该如何进行这个替换操作？
英文:
I'm using github actions for creating new images and pushing them to a registry.
- name: Build the Docker image
run: docker build . --file Dockerfile --tag ${{secrets.DOCKER_USER}}/book:$GITHUB_SHA
This works perfectly. Now, I need to replace the value of the image. So I thought of using yq
apiVersion: apps/v1
kind: Deployment
spec:
template:
spec:
containers:
- image: xxxxx/book:main
- name: Replace Image
run: yq -i e '.spec.template.spec.containers.image |= ${{secrets.DOCKER_USER}}/guestbook:$GITHUB_SHA' argo/deployment.yaml
But getting this error Error: 1:43: invalid input text "xxxx/book:..."
Error: Process completed with exit code 1.
How I would need to do this replacement?
答案1
得分: 2
使用正确的 JSON 路径表达式来定位 image 属性，并引用替换值。
示例：
$ yq '.spec.template.spec.containers.[0].image = "STRING"' argo/deployment.yaml
apiVersion: apps/v1
kind: Deployment
spec:
template:
spec:
containers:
- image: STRING
$ yq --version
yq (https://github.com/mikefarah/yq/) 版本 v4.34.1
英文:
Use the correct json path expression to the image property and quote the replacement value.
Example:
$ yq '.spec.template.spec.containers.[0].image = "STRING"' argo/deployment.yaml
apiVersion: apps/v1
kind: Deployment
spec:
template:
spec:
containers:
- image: STRING
$ yq --version
yq (https://github.com/mikefarah/yq/) version v4.34.1
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