英文:
Invocation of Python's descriptor protocol from super
问题
在Python的描述符指南中写道：
> 像super(A, obj).m这样的点查找会在obj.__class__.__mro__中搜索A之后紧接着的基类B，然后返回B.__dict__['m'].__get__(obj, A)。如果不是描述符，将返回m未更改的。
这似乎暗示属性m的搜索仅发生在类B的__dict__中，而类B是紧随A之后的基类，但我认为它应该在A之后的MRO中的所有基类中进行。我有遗漏什么吗？
英文:
In the Python Descriptor HowTo guide, it is written that:
> A dotted lookup such as super(A, obj).m searches obj.__class__.__mro__
> for the base class B immediately following A and then returns
> B.__dict__['m'].__get__(obj, A). If not a descriptor, m is returned
> unchanged.
This seems to suggest that the search for attribute m only happens in the __dict__ of class B, which is the base class immediately following A, however, I think it should happen in all of the base classes in the mro following A. Am I missing anything here?
答案1
得分: 1
查找基本上是通常的算法，但省略了一些开始的步骤：
- 在
type(m)的MRO中查找m，从A之后的类开始。
一旦找到了m，然后Python会检查m是否是描述符。如果是，将调用m.__get__，其返回值将是结果。否则，m本身就是结果。
英文:
The lookup is basically the usual algorithm, but with a couple of beginning steps skipped:
- <strike>Look for
minobj.__dict__.</strike> - <strike>Look for
mintype(m).__dict__.</strike> - Look for
min a class in the MRO oftype(m), starting with the class afterA.
Once m is found, then Python checks if m is a descriptor. If it is, m.__get__ is called and its return value is the result. Otherwise, m itself is the result.
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