英文:
Is it possible to create an inline try without a catch like shown
问题
以下是翻译好的部分：
我有一个情况，我想运行可能会出错但我不需要捕获错误的代码。
如果响应不是有效的JSON，那么结果应该是0：
我想使用以下代码：
var overallProgress = try {JSON.parse(text)} ? 0;
是否可以实现上述方式？
或者类似这样：
var overallProgress = try { JSON.parse(text)} catch(error) { 0 };
var overallProgress = try { JSON.parse(text)} catch(error) { overallProgress = 0 };
使用上述代码会出现错误。
我在下面找到了相关的帖子，但没有答案：
https://stackoverflow.com/questions/5764107/is-try-without-catch-possible-in-javascript
对于那些我伤害了眼睛的人：
var overallProgress = 0;
try { overallProgress = JSON.parse(text).overallProgress }
catch(error) { overallProgress = 0 };
英文:
I have this case where I want to run code that may have an error but I don't need to catch it.
If the response is not valid JSON then the result should be 0:
I'd like to use this code:
var overallProgress = try {JSON.parse(text)} ? 0;
Is it possible to the above?
Or something like this:
var overallProgress = try { JSON.parse(text)} catch(error) { 0 };
var overallProgress = try { JSON.parse(text)} catch(error) { overallProgress = 0 };
There are errors using the code above.
I found this related post below but no answer.
https://stackoverflow.com/questions/5764107/is-try-without-catch-possible-in-javascript
For anyone whose eyes I've hurt:
var overallProgress = 0;
try { overallProgress = JSON.parse(text).overallProgress }
catch(error) { overallProgress = 0 };
答案1
得分: 1
不直接支持，但可以使用立即调用函数表达式（IIFE）：
const overallProgress = (() => { try { return JSON.parse(text) } catch { return 0 } })();
不过，最好仍然将其格式化为多行：
const overallProgress = (() => {
try {
return JSON.parse(text);
} catch {
return 0;
}
})();
除了能够使用 const，它与使用两个赋值语句并没有太大的优势：
let overallProgress;
try {
overallProgress = JSON.parse(text);
} catch {
overallProgress = 0;
}
甚至可以简化为：
let overallProgress = 0;
try {
overallProgress = JSON.parse(text);
} catch {
/* 忽略：保持 `overallProgress` 的值不变 */
}
英文:
Not directly, no. But you can use an IIFE:
const overallProgress = (() => { try { return JSON.parse(text) } catch { return 0 } })();
I'd still format it as multiple lines though:
const overallProgress = (() => {
try {
return JSON.parse(text);
} catch {
return 0;
}
})();
Apart from being able to use const, it doesn't really have an advantage over simply using two assignments:
let overallProgress;
try {
overallProgress = JSON.parse(text);
} catch {
overallProgress = 0;
}
or even
let overallProgress = 0;
try {
overallProgress = JSON.parse(text);
} catch {
/* ignore: keep `overallProgress` value */
}
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