英文:
C# - How to keep the delimiters of Regex.Split in all resulting substrings?
问题
我想使用 Regex.Split 来根据分隔符进行拆分，并且让该分隔符拆分到所有子字符串中。
例如：
我有一个字符串 ""holidays//2024""，分隔符是 "''"，我希望得到以下结果：""holidays/""，""/2024""
这个 帖子展示了如何拆分并保留分隔符作为结果的独立元素。我还能够分别使用 Lookbehind "(?<=[])" 和 Lookahead "(?=[])"，每个都实现了所需结果的一半。我正在努力看如何同时使用两者（或其他解决方案）以在单个表达式中实现所需的结果。
有任何建议吗？
英文:
I'd like to use Regex.Split to split on a delimiter, and also have that delimiter split onto all substrings.
For Example:
I have a string "holidays/*/2024", and separator '*' and I want to have following: "holidays/*","*/2024"
This thread shows how to split and keep the separators as their own elements of the result. I have also been able to use Lookbehind (?<=[*]) and Lookahead (?=[*]) separately, each achieving half of the desired result. I am struggling to see how to use both (or alternative solutions) to accomplish the desired result in a single expression.
Any suggestions?
答案1
得分: 1
使用正则表达式分割字符串。
using System;
using System.Text.RegularExpressions;
public class Program
{
public static void Main()
{
string input = "holidays/*/2024";
string pattern = @"(?<=\*)|\*(?=/)";
string[] substrings = Regex.Split(input, pattern);
foreach (string substring in substrings)
{
Console.WriteLine(substring);
}
}
}
输出
holidays/
/2024
希望这有所帮助！
英文:
To split a string using Regex.
using System;
using System.Text.RegularExpressions;
public class Program
{
public static void Main()
{
string input = "holidays/*/2024";
string pattern = @"(?<=\*)|\*(?=/)";
string[] substrings = Regex.Split(input, pattern);
foreach (string substring in substrings)
{
Console.WriteLine(substring);
}
}
}
Output
holidays/
/2024
I hope this helps!
答案2
得分: 0
我不了解C#，但一个简单的循环应该足够：
string[] splitted = text.Split(delimiter);
for (var i = 0; i < splitted.Length; i++) {
var fragment = splitted[i];
if (i > 0) {
fragment = delimiter + fragment;
}
if (i < splitted.Length - 1) {
fragment += delimiter;
}
Console.WriteLine(fragment);
}
你可以在 dotnetfiddle.net 上尝试它。
英文:
I don't know C#, but a simple loop should be enough:
string[] splitted = text.Split(delimiter);
for (var i = 0; i < splitted.Length; i++) {
var fragment = splitted[i];
if (i > 0) {
fragment = delimiter + fragment;
}
if (i < splitted.Length - 1) {
fragment += delimiter;
}
Console.WriteLine(fragment);
}
Try it on dotnetfiddle.net.
答案3
得分: 0
以下是翻译好的部分：
另一个解决方案是使用这个看起来很可怕的正则表达式：
Regex re = new Regex(
@"
(?:^|\*) # 匹配并捕获字符串的开头或 '*',
(?= # 然后
([^*]+) # 一个包含 1 个或多个非 '*' 字符的组，接着是
(\*|$) # 另一个包含 '*' 或字符串结尾的组。
)
",
RegexOptions.IgnorePatternWhitespace
);
...然后使用 .Join() 在每个匹配中的组中获取最终结果：
MatchCollection matches = re.Matches(text);
foreach (Match match in matches) {
Console.WriteLine(
String.Join("", (
from Group matchGroup in match.Groups
where matchGroup.ToString() != ""
select matchGroup.ToString()
))
);
}
英文:
Another solution is to use this horrible-looking regex:
Regex re = new Regex(
@"
(?:^|\*) # Match and capture either the beginning of string or '*',
(?= # then
([^*]+) # a group 1+ non-'*' characters, followed by
(\*|$) # another group of '*' or the end of string.
)
",
RegexOptions.IgnorePatternWhitespace
);
...then .Join() the groups in each match to get the final result:
MatchCollection matches = re.Matches(text);
foreach (Match match in matches) {
Console.WriteLine(
String.Join("", (
from Group matchGroup in match.Groups
where matchGroup.ToString() != ""
select matchGroup.ToString()
))
);
}
Try it on dotnetfiddle.net.
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