英文:
How to unlist when converting dataframe to matrix?
问题
I want to coerce a numeric dataframe into matrix and want to retain the row/column names. I tried to unlist.
mat <- as.matrix(unlist(df))
Input:
> dput(df)structure(list(TCGA.2K.A9WE.01A = c("3.33370417925201", "3.26191613710211","2.98072012253114", "3.45442444300391", "3.23147506581216"),TCGA.2Z.A9J1.01A = c("3.34925376425734", "3.32510595062856","3.05313491041203", "3.63034209087263", "3.24014574406411" ),TCGA.2Z.A9J3.01A = c("3.30349695880794", "3.33666480834738","3.08982082695446", "3.70172491168742", "3.27383206099273" ),TCGA.2Z.A9J5.01A = c("3.38096309720271", "3.38548662709543","3.00519898142942", "3.57422385519763", "3.43484025303272" ),TCGA.2Z.A9J6.01A = c("3.36824732623076", "3.31393112898833","3.28265423939019", "3.58687437256901", "3.33930301693651" )), row.names = c("AAAS", "AARSD1", "AASS", "ABHD11", "ABHD14A"), class = "data.frame")Data structure> class(df)[1] "data.frame"> typeof(df)[1] "list"
(Note: The provided text appears to be code and data. If you have any specific translation needs or questions, please let me know.)
英文:
I want to coerce a numeric dataframe into matrix and want to retain the row/column names. I tried to unlist.
mat <- as.matrix(unlist(df))
Input:
> dput(df)structure(list(TCGA.2K.A9WE.01A = c("3.33370417925201", "3.26191613710211","2.98072012253114", "3.45442444300391", "3.23147506581216"),TCGA.2Z.A9J1.01A = c("3.34925376425734", "3.32510595062856","3.05313491041203", "3.63034209087263", "3.24014574406411"), TCGA.2Z.A9J3.01A = c("3.30349695880794", "3.33666480834738","3.08982082695446", "3.70172491168742", "3.27383206099273"), TCGA.2Z.A9J5.01A = c("3.38096309720271", "3.38548662709543","3.00519898142942", "3.57422385519763", "3.43484025303272"), TCGA.2Z.A9J6.01A = c("3.36824732623076", "3.31393112898833","3.28265423939019", "3.58687437256901", "3.33930301693651")), row.names = c("AAAS", "AARSD1", "AASS", "ABHD11", "ABHD14A"), class = "data.frame")
Data structure
> class(df)[1] "data.frame"> typeof(df)[1] "list"
答案1
得分: 2
你可以直接使用as.matrix()，无需进行unlist()操作：
mat <- as.matrix(df)mode(mat) <- "numeric"
如果你选择使用unlist()，似乎需要更多步骤：
mat <- matrix(as.numeric(unlist(df)), ncol = ncol(df))dimnames(mat) <- list(row.names(df), names(df))
英文:
You can apply as.matrix() directly without unlist()'ing:
mat <- as.matrix(df)mode(mat) <- "numeric"
If you rather unlist() it seems there will be more steps:
mat <- matrix(as.numeric(unlist(df)), ncol = ncol(df))dimnames(mat) <- list(row.names(df), names(df))
答案2
得分: 0
你可以将每一列转换为数字，然后将其放入一个矩阵中，如下所示：
as.matrix(sapply(df, as.numeric))# 添加行名row.names(mat) <- row.names(df)
英文:
You can covert each column to a numeric then put it into a matrix like so:
as.matrix(sapply(df,as.numeric))#add row namesrow.names(mat) <- row.names(df)
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论