英文:
Oracle - Check the presence of columns (yes/no) in a table
问题
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英文:
I am trying to write an Oracle query that accepts multiple columns of a table and returns rows for each column with a flag whether the input column exists or not?
Table DDL -
CREATE TABLE orders
(
id NUMBER(10),
order_mode VARCHAR2(8),
cust_id NUMBER(6),
status NUMBER(2)
)
To find out which column is present in the table, I execute below query. But it fails with the error message "SQL Error [936][42000]: ORA -00936: missing expression" fail.
SELECT column_name,
exists (
SELECT 1
FROM all_tab_columns
WHERE table_name = 'ORDERS'
AND column_name IN ('ORDER_MODE', 'CUST_ID', 'ABC')
) AS exists_one_zero
FROM dual;
The below query also fails with "SQL Error [904] [42000]: ORA-00904: COLUMN_NAME: invalid identifier".
SELECT column_name,
CASE WHEN exists (
SELECT 1
FROM all_tab_columns
WHERE table_name = 'ORDERS'
AND column_name IN ('ORDER_MODE', 'CUST_ID', 'ABC')
) THEN 'Yes' ELSE 'No' END AS exists_yes_no
FROM dual;
May I know what is the problem in above queries ?
答案1
得分: 2
Your first query fails because Oracle does not allow a predicate such as exists
in the select
clause like that; some databases would turn it into a boolean value, but in Oracle, you need to wrap the predicate in a case
expression (it will work in 23c though).
In the second query, the problem is that column_name
is not defined in the outer select
, which is from dual
(only the inner select sees that column).
Overall, I would recommend changing the logic to generate a fixed list of columns as rows, then check their presence in all_tab_columns
with exists
:
select c.column_name,
case when exists (
select 1
from all_tab_columns t
where t.table_name = 'ORDERS' and t.column_name = c.column_name
) then 'YES' else 'NO' end exists_yes_no
from (
select 'ORDER_MODE' as column_name from dual
union all select 'CUST_ID' from dual
union all select 'ABC' from dual
) c
You could take this one step further and make the table name a variable as well, so you could perform the same check across tables:
select c.column_name,
case when exists (
select 1
from all_tab_columns t
where t.table_name = c.table_name and t.column_name = c.column_name
) then 'YES' else 'NO' end exists_yes_no
from (
select 'ORDERS' table_name, 'ORDER_MODE' as column_name from dual
union all select 'CUSTOMERS', 'CUST_ID' from dual
) c
Side note: I would recommend adding the column OWNER
to the WHERE
clause of the ALL_TAB_COLUMNS
lookup, since different tables may have the same name in different schemas. Alternatively, consider querying USER_TAB_COLUMNS
, which lets you access your schema only.
英文:
Your first query fails because Oracle does not allows a predicate such as exists
in the select
clause like that; some database would turn it to a boolean value, but in Oracle you need to wrap the predicate in a case
expression (it will work in 23c though).
In the second query, the problem is that column_name
is not defined in the outer select
, which is from dual
(only the inner select sees that column).
Overall, I would recommend changing the logic to generate a fixed list of columns as rows, then check their presence in all_tab_columns
with exists
:
select c.column_name,
case when exists (
select 1
from all_tab_columns t
where t.table_name = 'ORDERS' and t.column_name = c.column_name
) then 'YES' else 'NO' end exists_yes_no
from (
select 'ORDER_MODE' as column_name from dual
union all select 'CUST_ID' from dual
union all select 'ABC' from dual
) c
You could took this one step forward and make the table name a variable as well, so you could perform the same check across tables:
select c.column_name,
case when exists (
select 1
from all_tab_columns t
where t.table_name = c.table_name and t.column_name = c.column_name
) then 'YES' else 'NO' end exists_yes_no
from (
select 'ORDERS' table_name, 'ORDER_MODE' as column_name from dual
union all select 'CUSTOMERS', 'CUST_ID' from dual
) c
Side note: I would recommend adding column OWNER
to the WHERE
clause of the ALL_TAB_COLUMNS
lookup, since different tables may have the same name in different schemas. Alternatively consider querying USER_TAB_COLUMNS
, which lets you access your own schema only.
答案2
得分: 1
你不需要使用 EXISTS。而是可以左连接两个查询 - 一个定义要与表进行列名测试的列名列表,另一个从 all_tab_columns 中获取表的列名。使用 Case 表达式来检查存在性。
Select
l.COLUMN_NAME,
CASE WHEN c.COLUMN_NAME Is Null THEN 'NO' ELSE 'YES' END "EXISTS"
From
( Select 'ORDER_MODE' "COLUMN_NAME" From Dual Union All
Select 'CUST_ID' From Dual Union All
Select 'SOME_COL' From Dual ) l
Left Join
( Select COLUMN_NAME
From all_tab_columns
Where TABLE_NAME = 'ORDERS' And
OWNER = 'TAB_OWNER_NAME') c ON(c.COLUMN_NAME = l.COLUMN_NAME)
结果:
COLUMN_NAME EXISTS
ORDER_MODE YES
CUST_ID YES
SOME_COL NO
英文:
You don't need to use EXISTS. Instead you could Left Join two queries - the one that defines your list of column names to be tested against a table and the other fetching column names of your table from all_tab_columns. Check the existance using Case expression
Select
l.COLUMN_NAME,
CASE WHEN c.COLUMN_NAME Is Null THEN 'NO' ELSE 'YES' END "EXISTS"
From
( Select 'ORDER_MODE' "COLUMN_NAME" From Dual Union All
Select 'CUST_ID' From Dual Union All
Select 'SOME_COL' From Dual ) l
Left Join
( Select COLUMN_NAME
From all_tab_columns
Where TABLE_NAME = 'ORDERS' And
OWNER = 'TAB_OWNER_NAME') c ON(c.COLUMN_NAME = l.COLUMN_NAME)
--
-- R e s u l t :
-- COLUMN_NAME EXISTS
-- ----------- ------
-- ORDER_MODE YES
-- CUST_ID YES
-- SOME_COL NO
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