如何修改我的凯撒密码实现以将结果输出为单个字符串？

huangapple
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英文:

How can I modify my Caesar cipher implementation to output the result as a single string?

问题

我试图编写一个凯撒密码；每当它打印结果时，每个字符串都会创建一个新行，而不是一个单独的字符串。

这是输出：

Q

M

D

X

我希望输出像这样：QMDX。

  1. 这是代码：
  2. print("""
  3.            88             88
  4.            ""             88
  5.                           88
  6.  ,adPPYba, 88 8b,dPPYba,  88,dPPYba,   ,adPPYba, 8b,dPPYba,
  7. a8"     "" 88 88P'    "8a 88P'    "8a a8P_____88 88P'   "Y8
  8. 8b         88 88       d8 88       88 8PP""""""" 88
  9. "8a,   ,aa 88 88b,   ,a8" 88       88 "8b,   ,aa 88
  10.  `"Ybbd8"' 88 88`YbbdP"'  88       88  `"Ybbd8"' 88
  11.               88
  12.               88                                      """)
  14. alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
  16. direction = input("Type 'encode' to encrypt, type 'decode' to decrypt:\n")
  17. text = input("Type your message:\n").lower()
  18. shift = int(input("Type the shift number:\n"))
  20. def encrypt(text, shift):
  21.     for i in text:
  22.         encryption = ""
  23.         i_unicode = ord(i)
  24.         i_index = ord(i) - ord('A')
  25.         new_index = (i_index + shift) % 26
  26.         new_unicode = new_index + ord('A')
  27.         new_character = chr(new_unicode)
  28.         encryption = encryption + new_character
  30.         print(encryption)
  33. encrypt(text, shift)

谢谢！

英文:

I'm trying to write a Ceasar cipher; whenever it prints the result, each string creates a new line instead of a single string.

This is the output:

Q

M

D

X

I wanted the output to go like this: QMDX.

  1. Here is the code:
  2. print("""                                                             
  3.            88             88                                 
  4.            ""             88                                 
  5.                           88                                 
  6.  ,adPPYba, 88 8b,dPPYba,  88,dPPYba,   ,adPPYba, 8b,dPPYba,  
  7. a8"     "" 88 88P'    "8a 88P'    "8a a8P_____88 88P'   "Y8  
  8. 8b         88 88       d8 88       88 8PP""""""" 88          
  9. "8a,   ,aa 88 88b,   ,a8" 88       88 "8b,   ,aa 88          
  10.  `"Ybbd8"' 88 88`YbbdP"'  88       88  `"Ybbd8"' 88          
  11.               88                                             
  12.               88                                      """)
  16. alphabet = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
  18. direction = input("Type 'encode' to encrypt, type 'decode' to decrypt:\n")
  19. text = input("Type your message:\n").lower()
  20. shift = int(input("Type the shift number:\n"))
  22. def encrypt(text, shift):
  23.     for i in text:
  24.         encryption = ""
  25.         i_unicode = ord(i)
  26.         i_index = ord(i) - ord('A')
  27.         new_index = (i_index + shift) % 26
  28.         new_unicode = new_index + ord('A')
  29.         new_character = chr(new_unicode)
  30.         encryption = encryption + new_character
  32.         print(encryption)
  35.             
  36.         
  37.         
  39. encrypt(text, shift)

Thank you!

答案1

得分: 1

需要在for循环之外初始化encryption。现在它的值在每次编码新字母时都被重置，所以它不会变得更长。

这将导致以下结果：

  1. Q
  2. QM
  3. QMD
  4. QMDX

如果你只想要它打印一次，把print语句放在for循环之外。

然后它将输出：

  1. QMDX

如果有关如何在Python中创建凯撒密码的问题，一个更有效的方法是，如ShadowRanger建议的，使用string.maketrans：

  1. import string
  3. def caeserEncode(target, shift):
  4.     alphabet = \
  5.         string.ascii_lowercase + \
  6.         string.ascii_uppercase
  8.     encodedAlphabet = \
  9.         string.ascii_lowercase[shift:] + \
  10.         string.ascii_lowercase[0:shift] + \
  11.         string.ascii_uppercase[shift:] + \
  12.         string.ascii_uppercase[0:shift]
  13.     transTable = target.maketrans(alphabet, encodedAlphabet)
  14.     return target.translate(transTable)
  16. print(caeserEncode("testString", 2))
  17. # 输出 vguvUvtkpi
  19. print(caeserEncode("abc xyz", 2))
  20. # 输出 cde zab

请注意，代码中的"是HTML实体，表示双引号，实际代码中应该使用双引号或单引号。

英文:

You need to initialize encryption outside the for loop. Right now it's value is being reset every time you encode a new letter, so it isn't getting any longer.

  1. def encrypt(text, shift):
  2.     encryption = ""
  3.     for i in text:
  4.         i_unicode = ord(i)
  5.         i_index = ord(i) - ord('A')
  6.         new_index = (i_index + shift) % 26
  7.         new_unicode = new_index + ord('A')
  8.         new_character = chr(new_unicode)
  9.         encryption = encryption + new_character
  10.         
  11.         print(encryption)

This will result in:

  1. Q
  2. QM
  3. QMD
  4. QMDX

If you only want it to print once, put the print statement outside the for loop.

  1. def encrypt(text, shift):
  2.     encryption = ""
  3.     for i in text:
  4.         i_unicode = ord(i)
  5.         i_index = ord(i) - ord('A')
  6.         new_index = (i_index + shift) % 26
  7.         new_unicode = new_index + ord('A')
  8.         new_character = chr(new_unicode)
  9.         encryption = encryption + new_character
  10.         
  11.         print(encryption)

Then it will output:

  1. QMDX

In case this comes up for how to make a caeser cypher in python, a more efficient method is, as suggested by ShadowRanger, string.maketrans:

  1. import string
  3. def caeserEncode(target, shift):
  4.     alphabet = \
  5.         string.ascii_lowercase + \
  6.         string.ascii_uppercase
  8.     encodedAlphabet = \
  9.         string.ascii_lowercase[shift:] + \
  10.         string.ascii_lowercase[0:shift] + \
  11.         string.ascii_uppercase[shift:] + \
  12.         string.ascii_uppercase[0:shift]
  13.     transTable = target.maketrans(alphabet, encodedAlphabet)
  14.     return target.translate(transTable)
  16. print(caeserEncode("testString", 2))
  17. #output vguvUvtkpi
  19. print(caeserEncode("abc xyz", 2))
  20. #cde zab

huangapple
  • 本文由 发表于 2023年5月25日 09:51:17
  • 转载请务必保留本文链接：https://go.coder-hub.com/76328396.html
  • encryption
  • python
  • python-3.x
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