英文:
Django template render a nested dict with tuples
问题
这里是我的字典 =
基本上是一个字典的字典的元组列表。
我想通过Django模板渲染的是：
但我无法做到，这是我当前的Django模板：
上面的代码渲染出来是：
英文:
Here's my dict =
{
'123': {'metric_1': [('url_1', 'caption_1'), ('url_2', 'caption_2'), ('url_3', 'caption_3'), ('url_4', 'caption_4')], 'metric_2': [('url_1', 'caption_1'), ('url_2', 'caption_2'), ('url_3', 'caption_3'), ('url_4', 'caption_4')]},
'456': {'metric_1': [('url_1', 'caption_1'), ('url_2', 'caption_2'), ('url_3', 'caption_3'), ('url_4', 'caption_4')], 'metric_2': [('url_1', 'caption_1'), ('url_2', 'caption_2'), ('url_3', 'caption_3'), ('url_4', 'caption_4')]},
'789': {'metric_1': [('url_1', 'caption_1'), ('url_2', 'caption_2'), ('url_3', 'caption_3'), ('url_4', 'caption_4')], 'metric_2': [('url_1', 'caption_1'), ('url_2', 'caption_2'), ('url_3', 'caption_3'), ('url_4', 'caption_4')]},
}
it basically is a dict of a dict of a list of tuples.
what I'd like to render via Django template is:
123
metric_1
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
metric_2
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
456
metric_1
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
metric_2
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
789
metric_1
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
metric_2
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
but I'm not able to do so, here's my current Django template:
<div class="grid grid-cols-2 gap-2 p-2">
{% for one_analysis_id, all_metrics in url_dict.items %}
<table>
<tr><p>Analysis ID: {{ one_analysis_id }}</p></tr>
{% for metric_name, url_and_caption_tuple_list in all_metrics.items %}
<tr><p>{{ metric_name }}</p></tr>
<tr>
{% for url_and_caption_tuple in url_and_caption_tuple_list %}
<td><img width="350" height="300" src="{{ url_and_caption_tuple.0 }}"><div>{{ url_and_caption_tuple.1 }}</div></td>
{% endfor %}
</tr>
{% endfor %}
</table>
{% endfor %}
</div>
What the above code renders is:
123
metric_1
metric_2
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
456
metric_1
metric_2
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
789
metric_1
metric_2
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
url_1 url_2 url_3 url_4
caption_1 caption_2 caption_3 caption_4
Could anyone please provide any insight?
Thanks!
答案1
得分: 1
这里是您要求的代码部分的翻译：
<div class="grid grid-cols-2 gap-2 p-2">
{% for one_analysis_id, all_metrics in url_dict.items %}
<table class="table">
<tr><th>Analysis ID: {{ one_analysis_id }}</th></tr>
{% for metric_name, url_and_caption_tuple_list in all_metrics.items %}
<tr><th>{{ metric_name }}</th></tr>
<tr>
{% for url_and_caption_tuple in url_and_caption_tuple_list %}
<td>{{ url_and_caption_tuple.0 }}</td>
{% endfor %}
</tr>
<tr>
{% for url_and_caption_tuple in url_and_caption_tuple_list %}
<td>{{ url_and_caption_tuple.1 }}</td>
{% endfor %}
</tr>
{% endfor %}
</table>
{% endfor %}
</div>
请注意，这是原始HTML代码，其中包含了HTML实体编码（如<和>）以及模板标记（如{% ... %}和{{ ... }}）。
英文:
I am not promoting this way of doing it, but it is a working solution:
<div class="grid grid-cols-2 gap-2 p-2">
{% for one_analysis_id, all_metrics in url_dict.items %}
<table class="table">
<tr><th>Analysis ID: {{ one_analysis_id }}</th></tr>
{% for metric_name, url_and_caption_tuple_list in all_metrics.items %}
<tr><th>{{ metric_name }}</th></tr>
<tr>
{% for url_and_caption_tuple in url_and_caption_tuple_list %}
<td>{{ url_and_caption_tuple.0 }}</td>
{% endfor %}
</tr>
<tr>
{% for url_and_caption_tuple in url_and_caption_tuple_list %}
<td>{{ url_and_caption_tuple.1 }}</td>
{% endfor %}
</tr>
{% endfor %}
</table>
{% endfor %}
</div>
As I said already in the comments, this would better be handled inside of the view's logic and be passed to the template in an easily digestible format.
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