Generate JSON key-value dictionary using SQL Server with multiple rows.

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英文:

Generate JSON key Value dictionary using SQL Server with multiple rows

问题

尝试找出将多行数据转换为单行KeyValue数组的方法。

原始数据:

id FkId name value
83713 1024180 Name1 Value1
83714 1024180 Name2 Value2

期望结果:

{ "Name1":"Value1", "Name2":"Value2" }

我尝试了不同的组合,使用Json Path和JSON_Array,但都没有得到我需要的结果。

SELECT JSON_ARRAY(s.name,s.value) AS result 
FROM tbl s 
WHERE FkId = 1024180 

结果是两行带有包装的数组:

row 0 ["Name1","Value1"],
row 1 ["Name2","Value2"]

尝试:

SELECT s.name, s.value 
FROM tbl s 
WHERE fkid= 1024180 
FOR JSON PATH

结果:

[{"name":"SpaceSubType","value":"Fee Earner"},{"name":"Department","value":"Property"}]

是否有合理的方法可以得到我想要的输出?

结果

根据Yitzhak的建议,我已经非常接近我需要的结果,但是Json Path现在转义了手动生成的字典。有没有办法去除这些转义字符?

格式化

select 
sa.Id as 'id',
s.id   as 'Sid',
(SELECT ('{' + STRING_AGG('"' + sp.name + '": "' + sp.value + '"', ',') + '}') as barf FROM  tbl sp where foo = s.id) as properties
     from TblA sa
	 inner join TblB s on s.id = sa.Sid
	 Where sa.Sid = '04000772'
	 For Json path, 
	 INCLUDE_NULL_VALUES 

结果

[
    {
        "id": "04000772",
        "Sid": 1024180,
        "Properties": "{\"Name1\": \"Value1\",\"Name2\": \"Value2\"}"
    }
]

根据下面的评论,这是构建字符串后进行转义的方法。

s.id as Sid, json_query((select '{'+string_agg('"' + string_escape(name, 'json') + '":"'+isnull(string_escape(value, 'json'),'null')+'"', ',')+'}' from tableX)) as properties
英文:

Trying to figure out how to convert multiple rows of data to a single row of KeyValue array.

Raw data:

id FkId name value
83713 1024180 Name1 Value1
83714 1024180 Name2 Value2

Desired result:

{ "Name1":"Value1", "Name2":"Value2" }

I have tried different combos using Json Path and JSON_Array.. neither are resolving to what I need.

SELECT JSON_ARRAY(s.name,s.value) AS result 
FROM tbl s 
WHERE FkId = 1024180 

Result is two rows with wrappers:

row 0 ["Name1","Value1"],
row 1 ["Name2","Value2"]

Tried:

SELECT s.name, s.value 
FROM tbl s 
WHERE fkid= 1024180 
FOR JSON PATH

Result:

[{"name":"SpaceSubType","value":"Fee Earner"},{"name":"Department","value":"Property"}]

Is there a reasonable way to get the output I am trying for?

results

Applying Yitzhak's recommendation I am super close to what I need however the json path is now escaping the manually generated dictionary. Any idea if possible to somehow trim those escape chars out?

formatted

select 
sa.Id as 'id',
s.id   as 'Sid',
(SELECT ('{' + STRING_AGG('"' + sp.name + '": "' + sp.value + '"', ',') + '}') as barf FROM  tbl sp where foo = s.id) as properties
     from TblA sa
	 inner join TblB s on s.id = sa.Sid
	 Where sa.Sid = '04000772'
	 For Json path, 
	 INCLUDE_NULL_VALUES 

result

[
    {
        "id": "04000772",
        "Sid": 1024180,
        "Properties": "{\"Name1\": \"Value1\",\"Name2\": \"Value2\"}"
    }
]

as per comments below.. this is the ticket to escaping the string once built.

…s.id as Sid, json_query((select '{'+string_agg('"'+string_escape(name, 'json') +'":'+isnull('"'+string_escape(value, 'json')+'"', 'null'), ',')+'}' from tableX)) as properties

答案1

得分: 1

请尝试以下解决方案。

从SQL Server 2017开始,它将起作用。

SQL

-- DDL和示例数据填充,开始
DECLARE @tbl TABLE (id INT PRIMARY KEY, FkId INT, name VARCHAR(20), value VARCHAR(20));
INSERT @tbl (id, FkId, name, value) VALUES
(83713, '1024180', 'Name1', 'Value1'),
(83714, '1024180', 'Name2', 'Value2');
-- DDL和示例数据填充,结束

SELECT '{' + STRING_AGG('"' + name + '": "' + value + '"', ',') + '}'
FROM @tbl
WHERE fkid = 1024180

Output

{
    "Name1": "Value1",
    "Name2": "Value2"
}
英文:

Please try the following solution.

It will work starting from SQL Server 2017 onwards.

SQL

-- DDL and sample data population, start
DECLARE @tbl TABLE (id INT PRIMARY KEY, FkId INT, name VARCHAR(20), value VARCHAR(20));
INSERT @tbl (id, FkId, name, value) VALUES
(83713, '1024180', 'Name1', 'Value1'),
(83714, '1024180', 'Name2', 'Value2');
-- DDL and sample data population, end

SELECT '{' + STRING_AGG('"' + name + '": "' + value + '"', ',') + '}'
FROM @tbl
WHERE fkid = 1024180

Output

{
    "Name1": "Value1",
    "Name2": "Value2"
}

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  • 本文由 发表于 2023年5月25日 04:36:09
  • 转载请务必保留本文链接:https://go.coder-hub.com/76327235.html
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